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2 years ago

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What is the degree of the polynomial below? 4x3+3x2+6x+5 A. 2 B. 1 C. 3 D. 0

1 answer:

dybincka [34]2 years ago

4 0

Answer:

Answers: 3

Step-by-step explanation:

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Let r(t)=⟨t2,1−t,4t⟩. calculate the derivative of r(t)⋅a(t) at t=5, assuming that a(5)=⟨−4,4,−5⟩ and a′(5)=⟨−5,9,3⟩

erastovalidia [21]

$\mathbf r(t)=\langle t^2,1-t,4t\rangle$
$\implies\mathbf r'(t)=\langle 2t,-1,4\rangle$

$\dfrac{\mathrm d(\mathbf r(t)\cdot\mathbf a(t))}{\mathrm dt}\bigg|_{t=5}=\mathbf r'(5)\cdot\mathbf a(5)+\mathbf r(5)\cdot\mathbf a'(5)$
$=\langle10,-1,4\rangle\cdot\langle-4,4,-5\rangle+\langle25,-4,20\rangle\cdot\langle-5,9,3\rangle$
$=(-40-4-20)+(-125-36+60)$
$=-165$

6 0

3 years ago

What is the solution set of 4x^2 - 36 = 0?

Leto [7]

<span>4x^2 - 36 = 0 ( Original equation )

4x^2 = 36 ( Add 36 to both sides )

x^2 = 9 ( Divide by 4 on both sides )

x = 3 , -3 ( Take the square root of 9 )

Solution set: { +3 , -3 } answer is x = +3 , x = -3</span>

6 0

3 years ago

Read 2 more answers

F(x) = 3x^3 - 2x^2 - 11x + 10; (x + 2)<br><br> I need to factor and find the zeros.

Ratling [72]

Answer:

$\textsf{Factored function}: \quad f(x)=(x+2)(3x-5)(x-1)$

$\textsf{Zeros}: \quad x=-2, \quad x=\dfrac{5}{3},\quad x=1$

Step-by-step explanation:

<u>Given function</u>:

$f(x)=3x^3-2x^2-11x+10$

If (x + 2) is a factor then:

$\implies f(x)=(x+2)(ax^2+bx+c)$

Expand:

$\implies f(x)=ax^3+bx^2+cx+2ax^2+2bx+2c$

$\implies f(x)=ax^3+2ax^2+bx^2+2bx+cx+2c$

$\implies f(x)=ax^3+(2a+b)x^2+(2b+c)x+2c$

To find <em>a</em>, compare the coefficients of x³:

$\implies a=3$

To find <em>b</em>, substitute the found value of <em>a</em> into the coefficient for x² and compare:

$\implies 2a+b=-2$

$\implies 2(3)+b=-2$

$\implies b=-8$

To find <em>c</em>, compare the constants:

$\implies 2c=10$

$\implies c=5$

Therefore:

$\implies f(x)=(x+2)(3x^2-8x+5)$

Now factor (3x²-8x+5):

$\implies 3x^2-3x-5x+5$

$\implies 3x(x-1)-5(x-1)$

$\implies (3x-5)(x-1)$

Therefore the factored function is:

$\implies f(x)=(x+2)(3x-5)(x-1)$

<u>Zero Product Property</u>

$\boxed{\text{If \; $a \cdot b = 0$ \; then either \; $a = 0$ \;or \;$b = 0$ (or both)}.}$

To find the zeros, set each factor equal to zero and solve for x:

$\implies x+2=0 \implies x=-2$

$\implies 3x-5=0 \implies x=\dfrac{5}{3}$

$\implies x-1=0 \implies x=1$

Therefore, the zeros of the function are:

$x=-2, \quad x=\dfrac{5}{3},\quad x=1$

3 0

1 year ago

What two numbers multiply to make 12 but<br> add to make -7?

vichka [17]

Answer:

negative three and negative 4 :)

Step-by-step explanation:

7 0

3 years ago

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Review the graph of complex number z.<br> What is the modulus of<br> Z.

Serggg [28]

Answer: square root of 10

Step-by-step explanation:

8 0

3 years ago

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