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hoa [83]
3 years ago
6

How do I do I simplify these? (x-4)^3

Mathematics
1 answer:
galben [10]3 years ago
4 0
Multiply
4
4
by
3
3
.
x
12
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2w-x+5y+z=-3 3w+2x+2y-6z=-32 w+3x+3y-z=-47 5w-2x-3y+3z=49
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Girl how you gon get an answer to that

Step-by-step explanation:

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A data set includes 40 pulse rates of men, and those pulse rates have a mean of 67.3 beats per minute and a standard deviation o
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Answer:

The 99% confidence interval of the  standard deviation of the pulse rates of men is  

       [ 7.949 \  \ , \  14.387 ]

Step-by-step explanation:

From the question we are told that

  The  sample size is  n  =  40

  The mean is  \= x  = 67.3 \  beats \  per \  minute

  The standard deviation is  s =  10.3 \ beats \ per \  minute

Generally the degree of freedom is mathematically represented as

     df =  n- 1

=>  df =  40- 1

=>  df =  39

From the question we are told the confidence level is  99% , hence the level of significance is    

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=>   \alpha = 0.01

Generally from the chi distribution table the critical value  of   at a degree of freedom of is  

   X^2 _{\frac{\alpha }{2} , 39} =  65.476

Generally from the chi distribution table the critical value  of   at a degree of freedom of is  

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Generally the 99% confidence interval of the standard deviation of the pulse rates of men is mathematically represented as

  s \sqrt{\frac{n- 1}{X^2_{1- \frac{\alpha }{2} , n-1} } }\  \ , \ s \sqrt{\frac{n- 1}{X^2_{\frac{\alpha }{2} , n-1} } }

=>  10.3 \sqrt{\frac{40- 1}{65.476} }\  \ , \ 10.3 \sqrt{\frac{40- 1}{19.996} }

=>  [ 7.949 \  \ , \  14.387 ]

   

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