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Svet_ta [14]
2 years ago
7

What is the missing term? +1 4x -3 3x 12x²? 4x - 3

Mathematics
1 answer:
larisa [96]2 years ago
5 0

Answer:

83

Step-by-step explanation:

41 plus 36 plus 36 is 83 is the answer for me

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Find the measure of angle CED in the figure below. Enter only the number.
nikdorinn [45]

Answer:

∠ CED = 58°

Step-by-step explanation:

∠ CED and ∠ AED are adjacent angles and sum to 180° , then

∠ CED + 122° = 180° ( subtract 122° from both sides )

∠ CED = 58°

6 0
2 years ago
Read 2 more answers
1. Identify the answers to the following questions:
VashaNatasha [74]
Dmmm I’m also doing this
5 0
3 years ago
Suppose a ship's load has 10 containers in each row from one side to the other, 15 containers in each row from front to back, an
dsp73

Answer:

1200 Containers

Step-by-step explanation:

According To The Question, We Have

  • 10 Containers in each Row from one side to other ( 10 length )
  • 15 Containers in each Row From front Side To Back (15 Breadth)
  • 8 layers of Containers (8 Height)

By All this Data We Found That, Basically A Big Size Cuboid is Formed Here.

Now, For The Total Numbers Of Containers = 10×15×8 = 1200 Containers

8 0
3 years ago
IMANU PAYS 30 EACH MONTH FOR HIS GYM MEMBERSHIP WHAT IS THE CHANGE IN THE AMOUNT OF MONEY IN HIS ACCOUNT AFTER 2/3 OF YEAR
likoan [24]

240 is the answer to your question

4 0
3 years ago
What is the area of a regular hexagon with a distance from its center to a vertex of 1 cm? (Hint: A regular hexagon can be divid
devlian [24]
<h3>Answer:</h3><h3>Exact area = \frac{3}{2}\sqrt{3} square cm</h3><h3>Approximate area = 2.598 square cm</h3>

=================================================

Work Shown:

s = side length of equilateral triangle = 1 cm

A = area of equilateral triangle with side length 's'

A = \frac{\sqrt{3}}{4}*s^2

A = \frac{\sqrt{3}}{4}*1^2

A = \frac{\sqrt{3}}{4}

This is just one of the 6 equilateral triangles (see diagram below)

Multiply by 6 to get the area of all 6 equilateral triangles, or the entire hexagonal area

6*A = 6*\frac{\sqrt{3}}{4}

6A = \frac{3\sqrt{3}}{2}

6A \approx 2.598

4 0
3 years ago
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