Answer:
6a) i- 2hrs 36mins ii- 3hrs 12mins
b) car A≈ 76.9km/h car B≈ 62.5km/h
c)------
7a) 35km
b) car A=75km car B=60km
c) 30km
d) car A≈36mins car B≈48mins
Step-by-step explanation:
6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.
b) Using the answer from a, you divide 200km by the time.
For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6
∴ car A: 200/2.6≈ 76.92km/h
For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2
∴ car B: 200/3.2≈ 62.5km/h
7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.
b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).
c) Difference from car A line to car B:
155km-125km=30km
d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.
Hope this helps.
Answer:
The height is 12.9m
Step-by-step explanation:
First we have to find the distance from the corner of the flag to the opposite corner, for this we will use Pythagoras
In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides
h² = s1² + s2²
h² = 10² + 20²
h² = 100 + 400
h² = 500
h = √500
h = 22.36
Now that we know this measurement we can calculate the height of the flagpole
well to start we have to know the relationship between angles, legs and the hypotenuse
α = 30
a: adjacent = 22.36
o: opposite = ?
h: hypotenuse
sin α = o/h
cos α= a/h
tan α = o/a
we see that it has (angle, adjacent, opposite)
is the tangent
tan α = o/a
tan 30 = o/22.36
tan30 * 22.36 = o
12.9 = o
The height is 12.9m
Answer: Choice A
The fractions are not equivalent because the product of the numerator of the first fraction and the denominator of the second fraction is <u> 15 </u> , which is not equal to the product of the numerator of the second fraction and the denominator of the first fraction <u> 16 </u>
===================================================
Explanation:
We have the template
which cross multiplies to 
So if
was true, then
must be true as well, and vice versa.
The left side 3*5 turns into 15, while the right hand side 4*4 becomes 16. The 15 and 16 don't match up.
In short,
turns into
which is a false statement. So the original claim that
is also false.
The equivalent expression of
is 
<h3>How to determine the equivalent expression?</h3>
The expression is given as:

Expand the numerator

Divide 125 and 30 by 5

Apply the law of indices

Evaluate the exponent

Hence, the equivalent expression of
is 
Read more about equivalent expression at:
brainly.com/question/2972832
#SPJ1