Answer:
C
Step-by-step explanation:
Answer:
0.25
Step-by-step explanation:
We have a total of ten student, and three students are randomly selected (without replacement) to participate in a survey. So, the total number of subsets of size 3 is given by 10C3=120.
On the other hand A=Exactly 1 of the three selected is a freshman. We have that three students are freshman in the classroom, we can form 3C1 different subsets of size 1 with the three freshman; besides B=Exactly 2 of the three selected are juniors, and five are juniors in the classroom. We can form 5C2 different subsets of size 2 with the five juniors. By the multiplication rule the number of different subsets of size 3 with exactly 1 freshman and 2 juniors is given by
(3C1)(5C2)=(3)(10)=30 and
Pr(A∩B)=30/120=0.25
The answer is: 36
Because, bisecting the base of the triangle gives of two segments of five. This forms two triangles with base of 5 and altitude (in this case height) of 12. There exists a special pythagorean triplet triangled named 5-12-13 meaning if you have a right triangle with two of these sides then the unknown side is the number left out. In this case, the altitude forms a right angle on the base which allows the sides of the big isocs. triangle to be 13 giving us 13 + 13 + 10 to be the perimeter = 36.
Answer:
Okayy
Step-by-step explanation:
Since T is the centroid which is the center
Also T is a midpoint
Nt=tn=42
Hope this helps
Answer:
5x-5
Step-by-step explanation:
