Equation of the line in slope intercept form is
y = 1/4 * x + 5. Slope is 1/4. Intercept is 5.
If x= 4, y = (1/4)*4 + 5 = 6.
The point (4,6) lies on the line.
Equation of the line in point slope form is
(y - y1)= m * (x - x1) where m is slope & (x1,y1) is point on the line.
Substituting slope m= 1/4 & point (4,6),
Equation of the line in point-slope form is:
(y - 6) = 1/4 * (x - 4).
Sanjay C.
Answer:
Step-by-step explanation:
N is between points M and O
MN = x
MO = 3x - 6
NO = x + 1
The way it reads MN + NO = MO
x + x + 1 = 3x - 6
2x + 1 = 3x - 6
2x - 2x +1 = 3x -2x - 6
1 = x - 6
1 + 6 = x
x = 7
MO = 3x - 6
MO = 3*7 - 6
MO = 21 - 6
MO = 15
I will give in y=mx+b and ax+by=c form
using point slope form
y-y1=m(x-x1)
where the slope is m and a point on that line is (x1,y1)
slope between 2 points (x1,y1) and (x2,y2) is (y2-y1)/(x1-x1)
given
(6,-3) and (-4,-9)
slope=(-9-(-3))/(-4-6)=(-9+3)/(-10)=-6/-10=3/5
a point is (6,-3)
y-(-3)=3/5(x-6)
y+3=3/5(x-6)
y+3=3/5x-18/5
y=3/5x-33/5
-3/5x+y=-33/5
3x-5y=33
equation is
y=3/5x-33 or
3x-5y=33 or
y+3=3/5(x-6) or
y+9=3/5(x+4)
Hope this helps .. sorry if it’s wrong .
