Find an angle between 0 degrees and 360 degrees and that is coterminal with 1260 degrees.

Mathematics

1 answer:

GarryVolchara [31]2 years ago

7 0

Answer:

<h2><u><em>The 180 degrees angle.</em></u></h2>

Step-by-step explanation:

We can start by dividing 1260 / 360 = 1080. Therefore, a 1080 degrees angle would be coterminal with 360.

Now we take 1260 - 1080, to see how many degrees we have left, this gives us: 180, therefore, the angle between 0 and 360 that is coterminal with 1260 degrees is the 180 degrees angle.

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Solve the rational equation: 2x/x-4-2x-5/x^2-10x+24=-3/x-6

jek_recluse [69]

Answer:

D. X=6.08, x=-0.58

Step-by-step explanation:

Given the rational expression

$\frac{2x}{x-4}-\frac{2x-5}{x^2-10x+24} = \frac{-3}{x-6}\\\frac{2x}{x-4}-\frac{2x-5}{x^2-4x-6x+24} = \frac{-3}{x-6}\\\frac{2x}{x-4}-\frac{2x-5}{x(x-4)-6(x-4)} = \frac{-3}{x-6}\\ \\\frac{2x}{x-4}-\frac{2x-5}{(x-4)(x-6)} = \frac{-3}{x-6}\\Rerrange;\\\frac{2x-5}{(x-4)(x-6)} = \frac{2x}{x-4}+ \frac{3}{x-6}\\\frac{2x-5}{(x-4)(x-6)} = \frac{2x(x-6)+3(x-4))}{(x-4)(x-6)}\\$

Cancel out the denominator on both sides

$2x-5 = 2x(x-6)+3(x-4)\\Expand\\2x-5 =2x^2-12x+3x-12\\2x-5 = 2x^2-9x-12\\Equate \ to \ zero\\2x^2-9x-12-2x+5 = 0\\2x^2-11x - 7 = 0\\$

Factorize

$x = -(-11)\pm\frac{\sqrt{(-11)^2-4(2)(-7)} }{2(2)}\\x = 11\pm\frac{\sqrt{121+56} }{4}\\x = 11\pm\frac{\sqrt{177} }{4}\\x = 11\pm\frac{13.3 }{4}\\x = \frac{11+13.3}{4} \ and \ x = \frac{11-13.3}{4} \\x = 6.08 \ and \ - 0.58$