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ira [324]
3 years ago
6

* An ant is crawling around this cube. The cube is made of wire. Each side of the cube is 3 inches long. (Those sides are called

edges.) Points A and B are vertices of the cube.
What is the least distance the ant would have to crawl if it starts from point A, crawls along every edge of the cube, and returns to point A?

PLEASE EXPLAIN
Mathematics
1 answer:
ladessa [460]3 years ago
6 0
A cube has 12 edges and each edge is 3 inches. If the ant only crawls on the edges it would be a distance of 36 (3*12)
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Two angles in a triangle have measures of 13° and 65° what is the measure of the third angle
natulia [17]

Answer:

102

Step-by-step explanation:

All angles added together=180

180-13-65

180-78

102

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A pair of shoes that normally sells for $82.88 goes on sale for 35% off. Rounding up to the nearest cent, calculate the sale pri
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$54.00

Step-by-step explanation:

3 0
2 years ago
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To win at LOTTO in a certain state, one must correctly select 6 numbers from a collection of 52 numbers (1 through 52). The orde
miv72 [106K]

Answer:

The answer is 20,358,520

Step-by-step explanation:

Selecting 6 numbers from a collection of 52 numbers regardless of order involves a combination.

Note: if regards was taken into order of selection, this would be a permutation.

Hence, the different 6 number selections out of 52 is

52C6 = 52! / [6!*(52-6)!]

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7 0
3 years ago
1.) Use a property to write an equivalent expression for 12*(100-5). Which property did you use?
Jlenok [28]

1. 12*100 - 12*5

You would use the distributive property to get this equation (it is equivalent to the original one)

2. Um... There's no actual story for this problem; sorry I can't solve this problem



3 0
3 years ago
Read 2 more answers
Plz, help!!!! :[ <br> I don't know the answer<br> look at the pic
otez555 [7]

Answer:

174 in²

Step-by-step explanation:

(A1)= 9(5)= 45 in²

(A2)= 3(5)=15 in²

(A3)= 3(5)=15 in²

(A4)= 9(3)= 27 in²

(A5)= 9(5)= 45 in²

(A6)= 9(3)= 27 in²

(totalA)= 45+15+15+27+45+27= 174 in²

6 0
3 years ago
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