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ira [324]
3 years ago
6

* An ant is crawling around this cube. The cube is made of wire. Each side of the cube is 3 inches long. (Those sides are called

edges.) Points A and B are vertices of the cube.
What is the least distance the ant would have to crawl if it starts from point A, crawls along every edge of the cube, and returns to point A?

PLEASE EXPLAIN
Mathematics
1 answer:
ladessa [460]3 years ago
6 0
A cube has 12 edges and each edge is 3 inches. If the ant only crawls on the edges it would be a distance of 36 (3*12)
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The distance between the points (12,9) and (0,4) is A) 14 units B) 13 units C) 15 units D) 16 units
Juliette [100K]

Answer:

Option B  13 units is correct.

Step-by-step explanation:

The formula used to find distance between 2 points is:

d(P1,P2)=\sqrt{(x_{2} -x_{1})^2 + (y_{2} -y_{1})^2 }

x₁ = 12 x₂ = 0 y₁= 9 and y₂=4

Putting values in the formula:

=\sqrt{(0-12)^2+(4-9)^2}\\=\sqrt{(-12)^2+(-5)^2}\\=\sqrt{144+25} \\=\sqrt{169} \\=13

So, Option B 13 units is correct.

6 0
3 years ago
Read 2 more answers
Which of the following statements about f(x) is true
kap26 [50]
Answer is C I hope it helps
5 0
3 years ago
Which fractions are greater than -5/16 ?
AlladinOne [14]
-5/16 

Our choices:-

A.-3/8
 
 
 B.-11/12
 
 
 C.-1/4
 
 
<span> D.-1/8
</span>
Let us get all of them with a LCD

-1*2 = -2
8*2 = 16

-2/16 is not bigger than -5/16

-11/12 is bigger than -5/16 because half of 16 is 8.

-1*4 = -4
4*4= 16

-4/16 is not bigger than -5/16

-1/8 is smaller than -5/16

Final answer: -11/12 is the only fraction bigger than -5/16

3 0
3 years ago
Read 2 more answers
30 points!
madreJ [45]
You would start at (0,36) and then move to (1, 24) , (2,12), (3,0) because he gives out 12 bags per hour 
7 0
3 years ago
Read 2 more answers
A survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10. (a)
skad [1K]

Answer:

a) The 95% of confidence intervals for the average spending

(23.872 , 32.128)

b) The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.

The null hypothesis is accepted

A survey of 25 young professionals statistically that the population mean is less than $30

<u>Step-by-step explanation</u>:

Step:-(i)

Given data a survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10

The sample size 'n' = 25

The mean of the sample   x⁻  = $28

The standard deviation of the sample (S) = $10.

Level of significance ∝=0.05

The degrees of freedom γ =n-1 =25-1=24

tabulated value t₀.₀₅ = 2.064

<u>Step 2:-</u>

The 95% of confidence intervals for the average spending

((x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )

(28 - 2.064 \frac{10}{\sqrt{25} } ,28 + 2.064\frac{10}{\sqrt{25} } )

( 28 - 4.128 , 28 + 4.128)

(23.872 , 32.128)

a) The 95% of confidence intervals for the average spending

(23.872 , 32.128)

b)

Null hypothesis: H₀:μ<30

Alternative Hypothesis: H₁: μ>30

level of significance ∝ = 0.05

The test statistic

t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }

t = \frac{28-30 }{\frac{10}{\sqrt{25} } }

t = |-1|

The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.

The null hypothesis is accepted

<u>Conclusion</u>:-

The null hypothesis is accepted

A survey of 25 young professionals statistically that the population mean is less than $30

8 0
3 years ago
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