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2 years ago

Two fewer than a doubled number is the same as the number decreased by 38. Find the number.

1 answer:

4 0

Answer is 2n -2 = n-38

Reason
2 fewer means (-2) than
A doubled number is (2n)
Same as is (=)
The number decreased by 38 is (n-38)
Combine these
2n-2=n-38

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Suppose a is a positive number and b is a negative num-

nata0808 [166]

Answer:a is positive b is negative

Step-by-step explanation:

3 0

3 years ago

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2<br> -6x + 5y = 1<br> 6x + 4y = -10

Luba_88 [7]

Answer:

(-1,-1)

Step-by-step explanation:

finding y

-6x + 5y = 1

+ (6x + 4y = -10)

---------------------------

9y = -9

y = -1

finding x

-6x + 5(-1) = 1

-6x - 5 = 1

+ 5 = +5

-6x = 6

x= -1

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3 years ago

Solve 2x2 + 20x = −38. (1 point)

RoseWind [281]

Answer:

The solutions are $x=-5+\sqrt{6}$ and $x=-5-\sqrt{6}$

Step-by-step explanation:

we have

$2x^{2} +20x=-38$

Divide by $2$ both sides

$x^{2} +10x=-19$ ------> $x^{2} +10x+19=0$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +10x+19=0$

$a=1\\b=10\\c=19$

substitute

$x=\frac{-10(+/-)\sqrt{10^{2}-4(1)(19)}}{2(1)}$

$x=\frac{-10(+/-)\sqrt{100-76}}{2}$

$x=\frac{-10(+/-)\sqrt{24}}{2}$

$x=\frac{-10(+/-)2\sqrt{6}}{2}$

$x1=\frac{-10(+)2\sqrt{6}}{2}=-5+\sqrt{6}$

$x2=\frac{-10(-)2\sqrt{6}}{2}=-5-\sqrt{6}$

8 0

3 years ago

Read 2 more answers

Because Helen was prepared to pay cash for a yellow car with a marked price of $9200 she was given a discount of $1012 what perc

Liula [17]

Answer:

11%

Step-by-step explanation:

The percentage of the discount is 1012/9200 x 100 = 11%

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3 years ago

At winds speeds above 1000 centimeters per second (cm/sec), significant sand-moving events begin to occur. Wind speeds below 100

alisha [4.7K]

Answer:

Lower limit = 1007.95 cm/s

Upper limit = 1142.05 cm/s

Step-by-step explanation:

We have to calculate a 95% CI with population's standard deviation known.

The sample is size n=60, with mean M=1075.

The confidence interval can be expressed as:

$M-z*\sigma/\sqrt{n} \leq\mu\leq M+z*\sigma/\sqrt{n}$

For a 95% CI, the value of z=1.96.

$1075-1.96*265/\sqrt{60} \leq\mu\leq 1075+1.96*265/\sqrt{60} \\\\1075-67.05 \leq\mu\leq 1075+67.05\\\\ 1007.95 \leq\mu\leq 1142.05$

8 0

3 years ago