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2 years ago

Sounds are reflected best when bounced off [answer] hard surfaces.

Physics

1 answer:

yuradex [85]2 years ago

3 0

Sounds are reflected best when bounced off the flat surfaces.

<h3>What is a sound wave?</h3>

A sound wave is produced when a medium begins to vibrate. When an entity vibrates, a pressure wave is formed, which causes sound.

Since sound waves cannot easily pass through hard surfaces, they bounce off them instead, reflecting back to the source which they first came from.

When sound is reflected off of flat surfaces, it does so most effectively.

Hence the flat surface is the correct answer.

To learn more about the sound wave refer to;

brainly.com/question/11797560

#SPJ1

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Answer:

Velocity of throwing = 34.335 m/s

Explanation:

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3 years ago

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3 years ago

Read 2 more answers

1.)Two objects, one of m=20,000 kg, and another of 12,500 kg, are placed at a distance of 5 meters apart. What is the force of g

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1) $6.67\cdot 10^{-4} N$

The force of gravitation between the two objects is given by:

$F=G\frac{m_1 m_2}{r^2}$

where

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m2 = 12,500 kg is the mass of the second object

r = 5 m is the distance between the two objects

Substituting the numbers inside the equation, we find

$F=(6.67\cdot 10^{-11})\frac{(20,000 kg)(12,500 kg)}{(5 m)^2}=6.67\cdot 10^{-4} N$

2) $2.7\cdot 10^{-3} N$

From the formula in exercise 1), we see that the force is inversely proportional to the square of the distance:

$F \sim \frac{1}{r^2}$

this means that if we cut in a half the distance without changing the masses, the magnitude of the forces changes by a factor

$F'\sim \frac{1}{(r/2)^2}=4 \frac{1}{r^2}=4F$

So, the gravitational force increases by a factor 4. Therefore, the new force will be

$F' = 4 F=4(6.67\cdot 10^{-4} N)=2.7\cdot 10^{-3} N$

3) 12.5 Nm

The torque is equal to the product between the magnitude of the perpendicular force and the distance between the point of application of the force and the centre of rotation:

$\tau=Fd$