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3 years ago

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A space capsule having a mass of 9.0×10^2 kg is projected vertically upwards from the Earth’s surface with an initial kinetic en

ergy of 7.0×10^9 J. With no air resistance, determine the maximum distance from the center of the Earth attained by the capsule.

1 answer:

Setler [38]3 years ago

8 0

Answer:

sg

Explanation:

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Which image best represents an animal exhibiting kinetic energy

nignag [31]

Answer: It's D (The cheetah)

Explanation:

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3 years ago

In coming to a stop, a car leaves skid marks 85m long on the highway. Assuming a deceleration of 3.0m/s/s , estimate the speed o

muminat

Based on your question where a car leaves skid marks 85m long on the highway nad getting to stop. The deceleration of the car is 3m/s^2 to estimate the speed of the car just before braking first is to analyze the problem then apply the necessary formulas. the possible answer is 510m/s

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4 years ago

A book is pushed with an initial horizontal velocity of 5.0 meters per second off the top of a desk. What is the initial vertica

PSYCHO15rus [73]

Answer:

The Initial vertical velocity is zero

Explanation:

Given that,

A book is pushed with an initial horizontal velocity, Vx = 5 m/s

According to projectile motion, the horizontal component of velocity i.e., in X-axis remains the same though out its path.

The vertical velocity varies i.e., the velocity towards the Y- axis.

The velocity of the falling book in its trajectory is the resultant velocity. Due to the action of gravity, it keeps on increasing with time.

The resultant velocity is given by relation

$V_{R} = \sqrt{{V_{x}^{2}} +[ {gt}]^{2} }$

where

gt = Vy - vertical velocity

g - acceleration due to gravity

t - time

Since, the initial horizontal velocity at that instant is equal to the resultant velocity.

Vx = 5 m/s

$V_{R}$ = 5 m/s

So, on substituting in the above equation

Vy = 0 m/s

Therefore, the initial vertical velocity is equal to zero

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3 years ago

A Chevrolet Corvette convertible can brake to a stop from a speed of 60.0 mi/h in a distance of 123 ft on a level roadway. What

Digiron [165]

Answer:

83.1946504051 m

Explanation:

u = Initial velocity = $60\ mph=\dfrac{60\times 1609.34}{3600}=26.82233\ m/s$

s = Displacement = $123\ ft=\dfrac{123}{3.281}=37.4885705578\ m$

$\theta$ = Angle = $26^{\circ}$

$v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{0^2-26.82233^2}{2\times 37.4885705578}\\\Rightarrow a=-9.5954230306\ m/s^2$

Coefficient of friction

$\mu=-\dfrac{a}{g}\\\Rightarrow \mu=\dfrac{9.5954230306}{9.81}\\\Rightarrow \mu=0.978126710561$

$mg sin\theta - u mg cos\theta = ma\\\Rightarrow a=9.81(sin26-0.978126710561cos26)\\\Rightarrow a=-4.32382\ m/s^2$

$v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-26.82233^2}{2\times -4.32382}\\\Rightarrow s=83.1946504051\ m$

The stopping distance is 83.1946504051 m

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4 years ago

Determine the change in velocity of a car that start at rest and has a final velocity of 20 m/s north

romanna [79]

The change in velocity is 20 m/s to the north.

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4 years ago