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2 years ago

14

The value of \sqrt(-16) is not -4 because

2 answers:

aliina [53]2 years ago

8 0

Answer:

square roots are absolute values

Step-by-step explanation:

they cannot be any integer or negative number. they had to be an absolute value

grigory [225]2 years ago

5 0

Detailed Answer:

Negative numbers don't have real square roots since a square is either positive or 0.

Also, Square roots of negative numbers are called complex numbers which is a whole new division of numbers. √-2 could also be written as 2i where “i” means iota.

You might be interested in

How i do inequalities

pogonyaev

Answer:

Following the steps given below you can solve any inequality.

Step-by-step explanation:

I will give an example and explain you step by step of solving an inequality.

Consider an inequality: $2x+4 > 8$

In this inequality we need to find the value of x.

Step 1: Write the inequality

$2x+4 > 8$

Step 2: Subtract 4 on both sides of inequality

$2x-4 > 8-4\\2x>4$

Step 3: Now, you have divide both sides by 2 to get value of 4

$\frac{2x}{2}>\frac{4}{2}\\x>2$

So, solving the inequality we find value of x: $x>2$

Following these steps you can solve any inequality.

I hope it will help you.

4 0

3 years ago

There was 320 hamburgers and cheeseburgers sold combined there were three times the cheeseburgers sold as hamburgers how many ha

antoniya [11.8K]

Answer:

240

Step-by-step explanation:

h+c=320

c=3h ( since 3 times the cheeseburger)

Now plug in 3h for C

h+3h=320 = 4h=320

Now divide 320 by 4 to get "h" alone

h=80

now plug 80 back t the eqation of c=3h

so now it is...

c=3 x 80

which is 240

so ur andswer is 240

7 0

2 years ago

If Phil had 1 dollar, he bought 2 items (milk and cookie) how much change did he get back?

Luda [366]

Does it give any prices for either the milk or the cookie or both?

5 0

3 years ago

Let the universal set be the set of integers and let A = {x | x^2 ≤ 5}. Write A using the roster method.

Zarrin [17]

Answer:

Step-by-step explanation:

Given that Z the set of integers is the universal set and

A is given in set builder form.

$A = {x | x^2 ≤ 5}$

To convert this into roster form, we can find solutions for x

When $x^2\leq 5\\|x|\leq \sqrt{5} =2.236$

i.e. all integers lying between -2.236 and 2.236

The only integers satisfying this conditions are

-2,-1,0,1,2

Hence A in roster form is

A= ${-2,-1,0,1,2}$

8 0

4 years ago

if 2 people answered your question and they were both right but only one of them explained they answer who should I give brainli

lakkis [162]

The person who explained the answer because you can see how they got the answer or the evidence they used to get the answer

5 0

3 years ago