4 years ago

Simplifypls help me ASAP

1 answer:

3 0

$\dfrac{\left(\dfrac{4}{3}ab^3\right)\left(\dfrac{6}{2}a^4\right)}{a^5}=\dfrac{\left(\dfrac{\not4^2}{\not3_1}\cdot\dfrac{\not6^2}{\not2_1}\right)(aa^4)(b^3)}{a^5}=\dfrac{4a^5b^3}{a^5}=\boxed{4b^3}$

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ki77a [65]

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3 years ago

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AlekseyPX

I'll solve it algebraically

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multiply first equatoin by -1 and add to second

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<u>x-3y=12 +</u>
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3 years ago

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alukav5142 [94]

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