Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
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Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
I'm assuming this is a Pythagorean theorem problem. If so the answer would be √125
Answer:
answer: 15/16 Hope this helps!
Answer:
2 13/20
Step-by-step explanation:
Answer:
Arccos(0.9272) =0.383929333 radian
0.383929333 radian =(0.383929333*57.2957795)degrees
so, 21.99 degrees
Step-by-step explanation:
Rounding to the nearest we get 22 degrees
We know that,
1 radian is equal to 57.2957795
so we multiply the radian value 0.383929333 with it
