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2 years ago

Which is the correct dissociation equation for aluminum nitrate?

Chemistry

1 answer:

dangina [55]2 years ago

4 0

Answer:

C.) Al(NO₃)₃ (aq) ---> Al³⁺ (aq) + 3 NO₃ (aq)

Explanation:

A.) is incorrect because aluminum nitrate is able to dissociate. I other words, it is able to separate into the two ions that created it.

B.) is incorrect because, according to the reactant, there should be 3 nitrates present after dissociation. The dissociation equation is not balanced without this coefficient.

C.) is correct. The two ions that make up aluminum nitrate are Al³⁺ and NO₃⁻. Notice how the charges are not balanced. To make up for this difference, there must be 3 nitrates for every aluminum ion to keep the overall charge of the reaction (and aluminum nitrate) neutral.

D.) is incorrect because there should not be a coefficient of 3 in front of Al³⁺ and instead in front of NO₃.

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A student needs to conduct a reaction that combines chemicals A and B to synthesize product AB. If we write this as a chemical e

vladimir2022 [97]

Answer:A+B - AB

Element a reaction with element b to create the newest element ab

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3 years ago

PLEASE HELP WILL GIVE 20PTS AND WILL MARK BRAINLIEST FOR RIGHT ANSWER!!!

Marysya12 [62]

Answer:

C) 0.457

Explanation:

The ratio between O2 and H2O is 1:2 according to the balanced equation. You can find how many moles is O2 by : 5.12/22.4 = 0.22857 ( 1 mole = 22.4 litters)

Moles of H2O will be 0.22857 * 2 = 0.457142.

Therefore answer C)

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3 years ago

Una sustancia tiene una masa de 81632 g. Se logró desplazar aplicando un trabajo de 2800 J. Averigüe la distancia que logró move

Rudik [331]

Answer:

Supongo que su suma 81632 + 2800 = 84432, por lo que la distancia que logró mover el objeto fue 2800.

Explanation:

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3 years ago

If 0.600mol of chloride gas reacted with 0.500mol of aluminium metal to produce aluminium chloride,which reactant is in excess?h

Rus_ich [418]

Answer:

The balanced chemical equation: 2 Al + 3Cl2→ 2 AlCl3

Mole-mole relationship: 2 moles Al + 3 moles Cl2→ 2 moles AlCl3

Given: 0.600 moleCl2; 0.500 mole Al

Required: Excess reactant___; Number of moles of AlCl3 produced__

Solution: Use dimensional analysis using the mole-mole rel

0.600 mole Cl2 * 2 moles Al/3 moles Cl2 = 0.4 mole Al

0.5 mole Al* 3 moles Cl2/2 moles Al = 0.75 mole Cl2

Based on the given:

0.6mole Cl2 + 0.4 mole Al ( this is possible based on the given)

0.5mole Al + 0.75 mole Cl2 (this is not possible because the given is only 0.600 mole of Cl 2)

Answer: Excess reactant is Al; Limiting reactant is Cl2

The amount of AlCl3 produced = 0.6 mole Cl2 + 0.4 mole Al = 1.0 mole AlCl3

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3 years ago

What is the molecular formula of a substance that decomposes into 1.33 g of h and 21.3 g of o, and was found to have a molar mas

Tema [17]

<span>H2O2 First, let's determine how many moles of hydrogen and oxygen atoms we have. Start by looking up the atomic weights of those elements: Atomic weight hydrogen = 1.00794 Atomic weight oxygen = 15.999 Moles hydrogen = 1.33 g / 1.00794 g/mol = 1.319522987 mol Moles oxygen = 21.3 g / 15.999 g/mol = 1.331333208 mol We now have a ratio of 1.319522987 : 1.331333208 and we want a ratio of small integers that is close. Start by dividing all the numbers in the ratio by the smallest value, giving: 1 : 1.008950371 This ratio is acceptably close to 1:1 so I assume the formula is of the form HnOn where n is a small integer. Let's initially assume that n is 1, so the mass would be 1.00794 + 15.999 = 17.00694 Obviously 17 is far smaller than 34.1. So let's divide 34.1 by 17.00694 and see what n should be: 34.1 / 17.00694 = 2.005063815 So the formula we want is H2O2, which is hydrogen peroxide.</span>

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3 years ago