We have to calculate the number of carbon atoms present in 2-carat pure diamond.
The number of carbon atoms present in 2-carat pure diamond is: 0.19 X 10²³ number of carbon atom.
Diamond is one allotrope of carbon. Atomic mass of carbon is 12.
Mass of one mole carbon atom is 12 g. One mole carbon contains Avogadro's number i.e, 6.023 X 10²³ number of atoms.
0.40 g diamond contains 0.40/12 moles= 0.033 moles of carbon atom.
So, number of carbon atoms present in 0.40 g diamond (i.e, 0.033 mole diamond) is 0.033 X 6.023 X 10²³= 1.98 X 10²²=0.19 X 10²³ .
Therefore, 0.19 X 10²³ number of carbon atoms are in a 2-carat pure diamond that has a mass of 0.40 g
Answer: C-Fat deposits put a strain on the body.
Answer:
The correct answer is "True".
Explanation:
Inferential statistics derives from statistics that comprise the methods and procedures by which, using induction, it determines the properties of a statistical population from a sample of this population. The objective of this type of statistics is to obtain useful conclusions to be able to make deductions on a population, based on the information of the sample taken from it.
Have a nice day!
Answer:
339.2K
Explanation:
Using Charles law equation;
V1/T1 = V2/T2
Where;
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question,
V1 = 2.97 L
V2 = 3.42 L
T1 = 21.6°C = 21.6 + 273 = 294.6K
T2 = ?
Using V1/T1 = V2/T2
2.97/294.6 = 3.42/T2
Cross multiply
2.97 × T2 = 294.6 × 3.42
2.97T2 = 1007.532
T2 = 1007.532 ÷ 2.97
T2 = 339.236
The final temperature is 339.2K
Answer:
I' really don't know I'm sorry
