Question

What is the equation of the line that passes through the point (6,6) and has a slope of 5/3

Answer 1

Answer:

The answer is

$\huge y = \frac{5}{3} x - 4$

Step-by-step explanation:

To find an equation of a line given the slope and a point we use the formula

$y - y_1 = m(x - x_1)$

where

m is the slope

( x1 , y1) is the point

From the question the point is (6,6) and slope 5/3

We have

$y - 6 = \frac{5}{3} (x - 6) \\ y - 6 = \frac{5}{3} x - 10 \\ y = \frac{5}{3} x - 10 + 6$

We have the final answer as

$y = \frac{5}{3} x - 4$

Hope this helps you