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love history [14]
2 years ago
11

M x-2 20 L Find the value of x. A.2 B.4 C.6 D.8

Mathematics
1 answer:
valentina_108 [34]2 years ago
3 0

Answer:

X=4

Step-by-step explanation:

Eveything is explained in the pic. Hope that helps ;)

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Let A = −2 2 1 −3 1 1 2 0 −1 and B = 2 −1 0 1 2 1 −1 −2 4 . Use the matrix-column representation of the product to write each co
BigorU [14]

Answer:

AB = \left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]

Each column of AB is written as a linear combination of columns of Matrix A in the explanation below.

Step-by-step explanation:

A = \left[\begin{array}{ccc}-2&2&1\\-3&1&1\\2&0&-1\end{array}\right]

B= \left[\begin{array}{ccc}2&-1&0\\1&2&1\\-1&-2&4\end{array}\right]

We need to write each column of AB as a linear combination of the columns of A so we will multiply each column of A with each column element of B to get the column of AB. So,

AB Column 1 = 2 * \left[\begin{array}{ccc}-2\\-3\\2\end{array}\right]  + 1 \left[\begin{array}{ccc}2\\1\\0\end{array}\right] + (-1) \left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}-3\\-6\\5\end{array}\right]

AB Column 2 = (-1)\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right] + 2\left[\begin{array}{ccc}2\\1\\0\end{array}\right] + (-2)\left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}4\\3\\0\end{array}\right]

AB Column 3 = (0)\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right] + (1)\left[\begin{array}{ccc}2\\1\\0\end{array}\right] + 4\left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}6\\5\\-4\end{array}\right]

Finally, we can combine all three columns of AB to form the 3x3 matrix AB.

AB = \left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]

4 0
3 years ago
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