Answer:
Vrel_jon's = 15 [m/s] to the right
Explanation:
Relative velocity is defined as the relative motion between two bodies, taking into account the directions of motion.
Relative velocity is defined as the relative motion between two bodies, taking into account the directions of motion. The relative velocity is defined as the algebraic sum of the velocities, if the movements are opposite the vectors are subtracted, as will be done below.
Vrel = 20 - 5 = 15 [m/s]
A person watching Jon sees him moving to the right at a speed of 15 [m/s]
Answer:
25 seconds (rounded up to nearest one second)
Explanation:
Cheetah's speed = 91.8 km/h
Gazelle's speed = 77.9 km/h
Both animals are running at full speed with the gazelle 97.3 m ahead.
Converting their respective speeds to m/s ;
Cheetah's speed =
= 25.5 m/s
Gazelle's speed =
= 21.6 m/s (correct to one decimal place)
Assuming the gazelle stops, cheetah will run at 25.5 m/s - 21.6 m/s = 3.9 m/s to catch its prey (gazelle).
Time = distance ÷ speed
The time cheetah will take to catch its prey = 97.3 m ÷ 3.9 m/s = 24.94871795 s = 25 seconds (rounded up to nearest one second)
Answer:
Explanation:
From the question we are told that
The length of the wire is 
The mass of the wire is 
The tension is
The frequency of the beat heard by the second student is

The speed of the wave generated by the vibration of the wire is mathematically represented as

substituting values


The wire is vibrating in its third harmonics so the wavelength is

substituting values


The frequency of this vibration is mathematically represented as

substituting values


The speed of the second student (Observer) is mathematically represented as
![v_o = [\frac{f_b}{2f} ] * v](https://tex.z-dn.net/?f=v_o%20%20%3D%20%20%5B%5Cfrac%7Bf_b%7D%7B2f%7D%20%5D%20%2A%20v)
substituting values
![v_o = [\frac{8.30}{2* 730.3} ] * 365.15](https://tex.z-dn.net/?f=v_o%20%20%3D%20%20%5B%5Cfrac%7B8.30%7D%7B2%2A%20730.3%7D%20%5D%20%2A%20365.15)

Answer:
Explanation:
Radius of circular path of coin R = 12.5 x 10⁻²,
coefficient of static friction μs = .33
In order that the coin rotates in circular path , it requires centripetal force which is provided by friction. As speed of rotation increases , force of friction also increases to provide it required centripetal force. When the speed of rotation becomes too high so that frictional force can not compensate the increase in centripetal force then coin will start slipping or it starts moving with respect to turntable.
b ) At this point of time
centripetal force = limiting force of friction
mω² R = μs mg , m is mass of the coin , ω is angular velocity ,
ω² R = μs g
ω² x 12.5 x 10⁻², = .33 x 9.8
ω² = .33 x 9.8 / 12.5 x 10⁻²,
= 25.87
ω = 5.08 rad / s
2π / T = 5.08
T = 2π / 5.08
= 1.23 s .
Answer:
Hydrogen
Explanation:
(H) atom does not have any neutrons in it's tiny nucleus.