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soldier1979 [14.2K]
2 years ago
11

For an object on a flat surface, the force of gravity is 15 newtons downward and the normal force is 15 newtons upward. The appl

ied force is 10 newtons toward the left and the frictional force is 8 newtons toward the right. What is the magnitude and direction of the net force?
2 newtons toward the right
2 newtons upward
2 newtons toward the left
2 newtons downward
Physics
1 answer:
fgiga [73]2 years ago
5 0

Answer:

There is a net force of 2 N to the left.

With 8 N to the left the up/down and left/right forces are in balance.

The force left over is 2 N to the left.

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If it takes a ball dropped from rest 2.261 s to fall to the ground, from what height H was it released? Express your answer in m
algol [13]

Answer:

Height, H = 25.04 meters

Explanation:

Initially the ball is at rest, u = 0

Time taken to fall to the ground, t = 2.261 s

Let H is the height from which the ball is released. It can be calculated using the second equation of motion as :

H=ut+\dfrac{1}{2}at^2

Here, a = g

H=\dfrac{1}{2}gt^2            

H=\dfrac{1}{2}\times 9.8\times (2.261)^2

H = 25.04 meters

So, the ball is released form a height of 25.04 meters. Hence, this is the required solution.

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3 years ago
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Answer:

a) 0.25m

b) 5 m/s

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When the spring is compressed both boxes are moving with the same velocity, so applying the principle of linear momentum conservation:

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Now applying the principle of energy conservation:

K1+K2+U_{g1}-U_e=Kf+U_{g2}\\K1+0-U_e=K2+0\\U_e=K1+K2-kf\\\frac{1}{2}*k*x^2+=\frac{1}{2}*m1*v1^2+\frac{1}{2}*m1*v1^2-\frac{1}{2}*(m1+m2)*v^2\\\\x=\sqrt{\frac{2.00kg*(10m/s)^2+5.00kg*(3.00m/s)^2-7.00kg*(5m/s)^2}{1120N/m}}\\x=0.25m

We got that the maximum compression is 0.25m.

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I believe your answer would be D- Physical properties of matter effect the chemical properties of matter.

Hope this helps. Tell me if I'm right.

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