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soldier1979 [14.2K]
2 years ago
11

For an object on a flat surface, the force of gravity is 15 newtons downward and the normal force is 15 newtons upward. The appl

ied force is 10 newtons toward the left and the frictional force is 8 newtons toward the right. What is the magnitude and direction of the net force?
2 newtons toward the right
2 newtons upward
2 newtons toward the left
2 newtons downward
Physics
1 answer:
fgiga [73]2 years ago
5 0

Answer:

There is a net force of 2 N to the left.

With 8 N to the left the up/down and left/right forces are in balance.

The force left over is 2 N to the left.

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John is riding the bus to the next samuell football game. The bus is traveling to the right at 20 m/s and Jon is walking towards
Elenna [48]

Answer:

Vrel_jon's = 15 [m/s] to the right

Explanation:

Relative velocity is defined as the relative motion between two bodies, taking into account the directions of motion.

Relative velocity is defined as the relative motion between two bodies, taking into account the directions of motion. The relative velocity is defined as the algebraic sum of the velocities, if the movements are opposite the vectors are subtracted, as will be done below.

Vrel = 20 - 5 = 15 [m/s]

A person watching Jon sees him moving to the right at a speed of 15 [m/s]

4 0
3 years ago
A cheetah can run at a maximum speed
vivado [14]

Answer:

25 seconds (rounded up to nearest one second)

Explanation:

Cheetah's speed = 91.8 km/h

Gazelle's speed = 77.9 km/h

Both animals are running at full speed with the gazelle 97.3 m ahead.

Converting their respective speeds to m/s ;

Cheetah's speed = \frac{91.8 * 1000}{3600} = 25.5 m/s

Gazelle's speed = \frac{77.9 * 1000}{3600}  = 21.6 m/s (correct to one decimal place)

Assuming the gazelle stops, cheetah will run at 25.5 m/s - 21.6 m/s = 3.9 m/s to catch its prey (gazelle).

Time = distance ÷ speed

The time cheetah will take to catch its prey = 97.3 m ÷ 3.9 m/s = 24.94871795 s = 25 seconds (rounded up to nearest one second)

3 0
4 years ago
a student stands several meters in front of a smooth reflecting wall, holding a board on which a wire is fixed at each end. the
Andrew [12]

Answer:

Explanation:

From the question we are told that

      The length of the wire is  L  = 75.0cm = \frac{75}{100}  =  0.75 \  m

      The mass of the wire is  m  =  2.25 \  g  =  \frac{2.25}{1000} = 0.00225 \ kg

      The tension is  T  = 400 \ N        

       The frequency of the beat heard by the second student is

  f_b =  8.30\  beat/second

The speed of the wave generated by the vibration of the wire is mathematically represented as

           v  = \sqrt{\frac{TL}{m}}

substituting values

           v  = \sqrt{\frac{400 *0.75}{0.00225}}

          v  =  365.15 m/s

         The wire is vibrating in its third harmonics so the wavelength is  

                        \lambda  =  \frac{2L}{3}

substituting values

                        \lambda  =  \frac{2*0.75}{3}

                        \lambda  =  0.5 \ m

The frequency of this vibration is mathematically represented as  

              f =  \frac{v}{\lambda }

substituting values  

           f =  \frac{365.15}{0.5 }

          f =  730.3 Hz

The speed of the second student (Observer) is mathematically represented as

           v_o  =  [\frac{f_b}{2f} ] * v

substituting values    

         v_o  =  [\frac{8.30}{2* 730.3} ] * 365.15

        v_o  = 2.08 \ m/s

8 0
3 years ago
A coin rests 12.5 cm from the center of a turntable. The coefficient of static friction between the coin and turntable surface i
AlladinOne [14]

Answer:

Explanation:

Radius of circular path of coin R = 12.5  x 10⁻²,

coefficient of static friction μs = .33

In order that the coin rotates in circular path , it requires centripetal force which is provided by friction. As speed of rotation increases , force of friction also increases to provide it required centripetal force. When the speed of rotation becomes too high so that frictional force can not compensate the increase in centripetal force then coin will start slipping or it starts moving with respect to turntable.

b ) At this point of time

centripetal force = limiting force of friction

mω² R = μs mg  , m is mass of the coin , ω is angular velocity ,

ω² R = μs g

ω² x 12.5 x 10⁻², = .33 x 9.8

ω² = .33 x 9.8 /  12.5 x 10⁻²,

= 25.87

ω = 5.08 rad / s

2π / T = 5.08

T = 2π / 5.08

= 1.23 s .

3 0
3 years ago
Which of the following atoms contain a nucleus with no neutrons.
Aleksandr-060686 [28]

Answer:

Hydrogen

Explanation:

(H) atom does not have any neutrons in it's tiny nucleus.

7 0
3 years ago
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