1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Katen [24]
3 years ago
11

What occurs when a swimmer pushes through the water to swim?

Physics
2 answers:
amid [387]3 years ago
6 0
When a swimmer pushes threw water to swim they are propelled forward because of the water resistance against the hand and feet.
ehidna [41]3 years ago
4 0

The correct answer to the question is that water will exert a force on the swimmer in forward direction, and swimmer will move along that direction.

EXPLANATION:

Before going to answer this question, first we have to understand Newton's third laws of motion.

Newton's third laws of motion states that, for every action, there is an equal and opposite reaction.

In the given question, the swimmer pushes the water in backward direction. This is the force of action. As per Newton's third law, the water must exert a reaction on the swimmer. The water applies a force on the swimmer in forward direction for which the swimmer can swim in the water.

You might be interested in
Why did boy (the observer) hear the pitch of the sound change? What does this tell us about the frequency of the sound? Support
timofeeve [1]

Answer:

<u>because of the doppler effect</u>

Explanation:

<em>Remember</em>, the doppler effect refers to the changes in sound (frequency of sound) observed by a person who is in a position relative to the wave source.

In this example, we notice as the train comes closer to the boy, the sound becomes louder also increasing the pitch slightly, the doppler effect sets in when the train passes the boy because the boy notices a decrease in the pitch of the moving train.

We learn from the change in the observed sound of the train that the frequency of the sound is determined by the distance of the observer from the wave source.

In other words, the closer the source of the sound to the observer; the faster it travels to the observer, however, the farther it is; the lesser it is; the greater the sound heard.

5 0
2 years ago
a boy looks at the reflection of his digital watch in a plane mirror and thinks the time is 10:11. what is the correct time?
Gekata [30.6K]

Answer:

11:10 will be the time. reflection causes the object to be flipped when you see its image at the mirror

6 0
3 years ago
A 3.5 kilogram object is swung in a circular path on the end of a 0.4 meter long string. the object makes one trip around the ci
jeyben [28]
Path length is 2*pi*0.4=2.512
Speed=distance/time
Speed =2.512/0.2=12.56m/s
6 0
3 years ago
A farmer hitches her tractor to a sled loaded with firewood and pulls it a distance
Delvig [45]

(a) The work done by the force applied by the tractor is 79,968.47 J.

(b) The work done by the frictional force on the tractor is 55,977.93 J.

(c) The total work done by  all the forces is 23,990.54 J.

<h3>Work done by the applied force</h3>

The work done by the force applied by the tractor is calculated as follows;

W = Fd cosθ

W = (5000 x 20) x cos(36.9)

W = 79,968.47 J

<h3>Work done by frictional force</h3>

W = Ffd cosθ

W = (3500 x 20) x cos(36.9)

W = 55,977.93 J

<h3>Net work done by all the forces on the tractor</h3>

W(net) = work done by applied force  -  work done by friction force

W(net) = 79,968.47 J -  55,977.93 J

W(net) = 23,990.54 J

Learn more about work done here: brainly.com/question/25573309

#SPJ1

4 0
1 year ago
The acceleration due to gravity on the surface of Jupiter is about 2.5 times the acceleration due to gravity on Earth’s surface.
Ann [662]

Answer: The correct answer is option C.

Explanation:

Weight = Mass × Acceleration

Let the mass of the space probe be m

Acceleration due to gravity on the earth = g

Weight of the space probe on earth = W

W=m\times g

Acceleration due to gravity on the Jupiter = g' = 2.5g

Weight of the space probe on earth = W'

W'=mg'=m\times 2.5g

\frac{W'}{W}=\frac{m\times 2.5g}{m\times g}

W'=2.5\times W

The weight of the space probe on the Jupiter will be 2.5 times the weight of the space probe on earth.

Hence, the correct answer is option C.

6 0
2 years ago
Other questions:
  • Define scalar and vector
    14·1 answer
  • How does conduction occur?
    9·1 answer
  • At what other angle will a thrown ball go the same distance as one thrown at an angle of 75 degrees?
    12·1 answer
  • If Team 4 wants to increase the horizontal distance that the skittles are projected through the air but keep the height as close
    15·1 answer
  • How is dark matter detected in the universe?
    15·1 answer
  • Explain what will happen if an object has high momentum or low momentum and a force is applied?
    10·1 answer
  • A space station shaped like a giant wheel has a radius of a radius of 153 m and a moment of inertia of 4.16 × 10⁸ kg·m² (when it
    15·1 answer
  • What is the change in atomic mass number when an atom emits an alpha particle?
    8·1 answer
  • A football player kicks a 0.94 kg football with a force of 2.4 N. Calculate the acceleration of the football as the player kicks
    6·2 answers
  • If a piece of ribbon were tied to a stretched string carrying a transverse wave, then how is the ribbon observed to oscillate?a.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!