Answer:
The wagon will move to the right.
Explanation:
From the question given above, the following data were obtained:
Force applied to the left (Fₗ) = 10 N
Force applied to the right (Fᵣ) = 30 N
Direction of the wagon =.?
To determine the direction in which the wagon will move, we shall determine the net force acting on the wagon. This can be obtained as follow:
Force applied to the left (Fₗ) = 10 N
Force applied to the right (Fᵣ) = 30 N
Net force (Fₙ) =?
Fₙ = Fᵣ – Fₗ
Fₙ = 30 – 10
Fₙ = 20 N to the right
From the calculations made above, the net force acting on the wagon is 20 N to the right. Hence the wagon will move to the right.
Answer:
Leak 1 = 3.43 m/s
Leak 2 = 2.42 m/s
Explanation:
Given that the top of the boot is 0.3 m higher than the leaks.
Let height H = 0.3m and the acceleration due to gravity g = 9.8 m/s^2
From the figure, the angle of the leak 1 will be approximately equal to 45 degrees. While the leak two can be at 90 degrees.
Using the third equation of motion under gravity, we can calculate the velocity of leak 1 and 2
Find the attached files for the solution and figure
Answer:
q=1.7346×10⁻⁶C
Explanation:
Since the electric field is perpendicular to the bottom and top of the cube,the total flux is equals the flux over the top of surface plus the flex over the lower surface
Ф(total)=Ф₃₀₀+Ф₂₃₀
But the flux is given by Ф=E.A=EACos(θ) where θ is the angle between Area vector and electric field
So
Ф(total)=E₃₀₀A Cos(180)+E₂₃₀ACos(0)
Ф(total)=A(E₃₀₀ - E₂₃₀)
The total flux is given by Gauss Law as:
Ф(total)=q/ε₀
q=ε₀Ф(total)
q=ε₀(A(E₃₀₀ - E₂₃₀))
Substitute the given values
q=(8.85×10⁻¹²){(70²)(100 - 60)}
q=1.7346×10⁻⁶C
17. C. Isotopes
18. Tracers
19. Alpha Decay
