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3 years ago

Determine which law is appropriate for solving the following problem.

Physics

2 answers:

Nostrana [21]3 years ago

8 0

Charles Law

Explanation:

Step 1:

It is given that the original volume of the gas is 250 ml at 300 K temperature and 1 atmosphere pressure. We need to find the volume of the same gas when the temperature is 350 K and 1 atmosphere pressure.

Step 2:

We observe that the gas pressure is the same in both the cases while the temperature is different. So we need a law that explains the volume change of a gas when temperature is changed, without any change to the pressure.

Step 3:

Charles law provides the relationship between the gas volume and temperature, at a given pressure

Step 4:

Hence we conclude that Charles law can be used.

kicyunya [14]3 years ago

5 0

Answer:

I agree with Rahulnair123427.

Charles Law

Explanation:

Step 1:

Step 2:

Step 3:

Charles law provides the relationship between the gas volume and temperature, at a given pressure

Step 4:

Hence we conclude that Charles law can be used.

Explanation:

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Oil tends to float on water because the density of oil is _____ the density of water.

Rama09 [41]

Oil is less dense than water so it tends to float on the top of the water. Hope this Helps!

7 0

3 years ago

What are some forces that come in pairs?

Nikolay [14]

Answer:

ACTION REACTION FORCES

Explanation:

When there is an action frce there will be a reaction force

3 0

3 years ago

A spaceship negotiates a circular turn of radius 2925 km at a speed of 29960 km/h. (a) What is the magnitude of the angular spee

emmainna [20.7K]

a) 0.0028 rad/s

b) $23.68 m/s^2$

c) $0 m/s^2$

Explanation:

When an object is in circular motion, the angular speed of the object is the rate of change of its angular position. In formula, it is given by

$\omega = \frac{\theta}{t}$

where

$\theta$ is the angular displacement

t is the time interval

The angular speed of an object in circular motion can also be written as

$\omega = \frac{v}{r}$ (1)

where

v is the linear speed of the object

r is the radius of the orbit

For the spaceship in this problem we have:

$v=29,960 km/h$ is the linear speed, converted into m/s,

$v=8322 m/s$

$r=2925 km = 2.925\cdot 10^6 m$ is the radius of the orbit

Subsituting into eq(1), we find the angular speed of the spaceship:

$\omega=\frac{8322}{2.925\cdot 10^6}=0.0028 rad/s$

When an object is in circular motion, its direction is constantly changing, therefore the object is accelerating; in particular, there is a component of the acceleration acting towards the centre of the orbit: this is called centripetal acceleration, or radial acceleration.

The magnitude of the radial acceleration is given by

$a_r=\omega^2 r$

where

$\omega$ is the angular speed

$r$ is the radius of the orbit

For the spaceship in the problem, we have

$\omega=0.0028 rad/s$ is the angular speed

$r=2925 km = 2.925\cdot 10^6 m$ is the radius of the orbit

Substittuing into the equation above, we find the radial acceleration:

$a_r=(0.0028)^2(2.925\cdot 10^6)=23.68 m/s^2$

When an object is in circular motion, it can also have a component of the acceleration in the direction tangential to its motion: this component is called tangential acceleration.

The tangential acceleration is given by

$a_t=\frac{\Delta v}{\Delta t}$

where

$\Delta v$ is the change in the linear speed

$\Delta t$ is the time interval

In this problem, the spaceship is moving with constant linear speed equal to

$v=8322 m/s$

Therefore, its linear speed is not changing, so the change in linear speed is zero:

$\Delta v=0$

And therefore, the tangential acceleration is zero as well:

$a_t=\frac{0}{\Delta t}=0 m/s^2$

5 0

3 years ago

Railroad car A, with mass 6275 kg, is traveling east at 6.5 m/s along a straight track. It strikes railroad car B, with mass 515

LekaFEV [45]

The speed of A and B immediately after collision is 5.28m/s

<u>Explanation:</u>

Mass of A is 6275kg

Speed of A is 6.5m/s

Mass of B is 5155kg

Speed of B is 3.8m/s

Track is frictionless.

A and B stick together.

speed of attached A and B = ?

mₐsₐ + mᵇsᵇ = (mₐ + mb) s

$6275 X 6.5 + 5155 X 3.8 = ( 6275 + 5155) X s\\\\s = \frac{40787.5 + 19589}{11430}\\ \\s = \frac{60376.5}{11430}\\ \\s = 5.28m/s$

Therefore, The speed of A and B immediately after collision is 5.28m/s

4 0

3 years ago

please help! need a answer as quick as possible please. i need help with questions 1 and 2 ! thank you

Mariulka [41]

Answer:

1.)When you arrive from school and you smell cookies baking in the kitchen your brain will tell you that you are hungry and that you should go to the kitchen at that point your sense organs like your nose helps you to detect that something is baking(cookies)and your nervous system (brain)will tell you that you are hungry and it will command/direct your brain to go to the kitchen then for you to eat the cookies and drink the milk the digestive system is going go help you to chew,swallow and digest the food which has been taken and when you also run to the kitchen at the beginning your brain will direct your skeletal and muscular system because the skeletons and muscles work hand in hand,and when you finish your meal the body will circulate some nutrients or minerals from the food or snack taken to other parts of the body for energy.

2.)When you sleep the whole body is asleep except the heart which needs to continue circulating blood around the whole system and sometimes the brain may not rest when you are sleeping it may continue to do it's work that's why some people usually sleep walk or sleep talk,it means the brain is not at rest and still doing some things....Thank you for the question I hope it is very useful to you.

7 0

3 years ago