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Delvig [45]
2 years ago
10

A 2kg block slides down a ramp which is at an incline of 25 degrees. Friction force is 4.86N. At what incline will the box slide

at a constant velocity
Physics
1 answer:
ehidna [41]2 years ago
6 0

The coefficient of kinetic friction between the block and the incline will be 0.133.

<h3>What is the cofficient of kinetic friction?</h3>

The ratio of the greatest kinetic friction force (F) between the surfaces in contact during movement begins to the normal (N) force is the coefficient of kinetic friction.

The complete question is;

"A block slides down an incline of an angle of 26° with an acceleration of 2.5 m/s^2. What is the coefficient of kinetic friction between the block and the incline?"

The given data in the problem is;

The coefficient of kinetic friction,(μ)=?

The minimum angle is such that the ladder may not slip is 25 degrees.

The coefficient of kinetic friction between the block and the incline is;

tanΘ=μ

tan 25=μ

tan 25°=-0.133

μ=-0.133

Hence the coefficient of kinetic friction between the block and the incline will be 0.133.

To learn more about the cofficient of static friction refer to;

brainly.com/question/17237604

#SPJ1

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Answer:

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Explanation:

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Where ΔM = change in momentum, m = mass of the object, Δv = change in velocity = v₂ - v₁

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(b)

Force: This can be defined as the ratio of the change in momentum of a body to the time required for the change.

F = ΔM/t.............................. Equation 2

Where F = force, ΔM = change in momentum, t = time.

Given: ΔM  = 4000 kgm/s, t = 50 second.

Substituting into equation 2

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3 years ago
A swan on a lake gets airborne by flapping its wings and running on top of the water. If the swan must reach a velocity of 6.00
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