Answer:
Step-by-step explanation:
We need to get m on one side all by itself. To achieve this, let's subtract both sides by 1.2 to get .
The graph shows the quadratic function f, and the table shows the quadratic function g.
1 answer:
Analyzing the quadratic functions, it is found that the correct option is D. The functions f and g have the same axis of symmetry, but the minimum value of f is less than the minimum value of g.
<h3>How to analyze the function?</h3>Looking at the graph, Function f has a minimum value of 1 at x = -3. Hence, the axis of symmetry is x = -3.
Function g has a minimum value of 6 at x = -3. Hence, the axis of symmetry is also x = -3.
Therefore, the functions f and g have the same axis of symmetry, but the minimum value of f is less than the minimum value of g.
Learn more about functions on:
#SPJ1
You might be interested in
(i) Given that
when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then
and this is a volume so it must be reported with units of cm³.
In Mathematica, you can first define the velocity function with
v[r_] := 0.30 - 3.33r^2
and additionally define the volume function with
V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]
Then get the desired volume by running V[0.30].
(ii) In full, the volume function is
Compute the integral:
In M, redefine the velocity function as
v[r_] := k*(R^2 - r^2)
(you can't use capital K because it's reserved for a built-in function)
Then run
Integrate[2 Pi v[r] r, {r, 0, R}]
This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with
Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]
which ensures that R is positive, and moreover a real number.