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Nookie1986 [14]
2 years ago
13

plumber a charges an initial fee of $45 plus a rate of $60 per hour. Plumber B charges $225 flat. Explain how you would determin

e the number of hours it will take for both plumbers to charge the same amount? HELP IM TAKING A TEST!
Mathematics
1 answer:
Hunter-Best [27]2 years ago
4 0

Answer:

3 Hours

Step-by-step explanation:

Plumber A.

Initial fee: $45

Per Hour: $60

Plumber B.

Full rate: $225

To determine the number of hours it will take for both plumbers to charge the same amount you have to start with $45.

Then add 60$ every hour.

$45 + $60 = $105

$105 + $60 = $165

$165 + $60 = $225

Therefore, it takes 3 hours for them to charge the same rate.

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Nezavi [6.7K]

Answer:

Frank's father waited 140 minutes all together

Step-by-step explanation:

Sorry if I'm wrong :/

6 0
3 years ago
LMNO is a parallelogram. If NM = x + 33 and OL = 4x + 9, find the value of x and then find NM and OL.
anyanavicka [17]
Because these are on opposite sides of the parallelogram, x + 33 = 4x + 9.

This gives you x = 8; OL = 41, NM = 41. 
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Simplify the expression.
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2^3z^9
A for question 1=8z^9

(-8ab)^2
(-8^2a^2b^2)
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Round 3,062.845 to 2 decimal places
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3,062.85 is de answer having on two decimals
4 0
3 years ago
Height of Dutch Men. Males in the Netherlands are the tallest, on average, in the world with an average height of 183 centimeter
trapecia [35]

Answer:

a) P(X

P(z

b) P(X>195) =P(Z>\frac{195-183}{10.5})=P(Z>1.143)

P(z>1.143)=1-P(Z

c) P(173

P(-0.953

P(-0.953

d) P(\bar X >190)=P(Z>\frac{190-183}{\frac{10.5}{\sqrt{1000}}}=21.08)

And using a calculator, excel ir the normal standard table we have that:

P(Z>21.08)=1-P(Z

So for this case we expect anyone with a heigth higher than 190 cm in a random sample of 1000.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(183,10.5)  

Where \mu=183 and \sigma=10.5

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability with the normal standard table or with excel:

P(z

Part b

P(X>195)

P(X>195) =P(Z>\frac{195-183}{10.5})=P(Z>1.143)

And we can find this probability with the normal standard table or with excel: using the complement rule

P(z>1.143)=1-P(Z

Part c

P(173

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(173And we can find this probability on this way:

P(-0.953

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.953Part d

Since the distributiion for X is normal then the distribution for the sample mean is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we eant this probability:

P(\bar X >190)=P(Z>\frac{190-183}{\frac{10.5}{\sqrt{1000}}}=21.08)

And using a calculator, excel ir the normal standard table we have that:

P(Z>21.08)=1-P(Z

So for this case we expect anyone with a heigth higher than 190 cm in a random sample of 1000.

3 0
3 years ago
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