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Zarrin [17]
2 years ago
14

In the reaction 2KC1(e) → 2K(s) + Cl₂(g), the K+

Chemistry
1 answer:
natta225 [31]2 years ago
5 0

Answer: (2) reduced by gaining electrons

Explanation:

The oxidation number of potassium changes from +1 to 0, meaning that it gained electrons, and was thus reduced.

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2. Which of these items would allow one scientist to reproduce the experiment of another scientist.
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Identify the product formed from the phosphorylation of adp.
yulyashka [42]
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Hence, the answer is ATP. 
4 0
3 years ago
Read 2 more answers
Many chemistry problems result in equations of the form
Gnom [1K]

Answer:

When this equation is solved, the two values of the unknown are 0.0643 and -0.082

Explanation:

Given

1.77 * 10^{-2} = \frac{x^2}{0.298 - x} --- the actual equation

Required

The values of x

We have:

1.77 * 10^{-2} = \frac{x^2}{0.298 - x}

Cross Multiply

1.77 * 10^{-2} * (0.298 - x)= x^2

Multiply both sides by 100

1.77  * (0.298 - x)= 100x^2

Open bracket

0.52746 - 1.77x= 100x^2

Rewrite as:

100x^2 + 1.77x - 0.52746 =0

Using quadratic formula:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

Where:

a = 100; b = 1.77; c = -0.52746

So, we have:

x = \frac{-1.77 \± \sqrt{1.77^2 - 4*100*- 0.52746 }}{2*100}

x = \frac{-1.77 \± \sqrt{214.1169}}{2*100}

x = \frac{-1.77 \± 14.63}{200}

Split

x = \frac{-1.77 + 14.63}{200}\ or\ x = \frac{-1.77 - 14.63}{200}

x = \frac{12.86}{200}\ or\ x = \frac{-16.40}{200}

x = 0.0643\ or\ x = -0.082

3 0
3 years ago
The student collects the H2 (g) produced by the reaction and measures the volume
BARSIC [14]

The question is incomplete, the complete question is;

The student collects the H2(g) produced by the reaction and measures its volume over water at 298 K after carefully equalizing the water levels inside and outside the gas-collection tube, as shown in the diagram below. The volume is measured to be 45.6mL . The atmospheric pressure in the lab is measured as 765 torr , and the equilibrium vapor pressure of water at 298 K is 24 torr .(i) The pressure inside the tube due to the H2(g)

Answer:

741 torr

Explanation:

From the question we can see that the atmospheric pressure in the lab is 765 torr.

The vapour pressure of water = 24 torr

From Dalton's law of partial pressure, we know that;

Total pressure = Pressure of the H2 + Partial pressure of water vapour

Therefore;

Pressure of H2 = Total pressure - Partial pressure of water vapour

Pressure of H2 = 765 torr - 24 torr = 741 torr

7 0
3 years ago
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