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denis-greek [22]
3 years ago
14

Explain what WHMIS is

Chemistry
1 answer:
White raven [17]3 years ago
7 0
Workplace Hazardous Materials Information System is the answer to this question. Hope it helps :)
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How many atoms are in 26.8 g Fe
Tatiana [17]

Answer:

2.881x10^23 atoms

Explanation:

From the studies of Avogadro's hypothesis, we discovered that 1mole of any substance contains 6.02x10^23 atoms.

Therefore 1mole of Fe contains 6.02x10^23 atoms.

Molar Mass of Fe = 56g/mol

56g of Fe contains 6.02x10^23 atoms.

Therefore, 26.8g of Fe will contain = (26.8x6.02x10^23) / 56 = 2.881x10^23 atoms

6 0
3 years ago
Use the given figure to complete the statement below.
FinnZ [79.3K]
Vertical now I need to fill 20 characters
7 0
4 years ago
Read 2 more answers
Which is the correct net ionic equation for the reaction of aqueous ammonia with nitric acid? Which is the correct net ionic equ
Svet_ta [14]

Answer:

The last option:

  • NH₃ (aq) +  H⁺ (aq)  →  NH₄⁺ (aq)

Explanation:

1) Word equation

  • Aqueous ammonia + nitric acid → aqueous ammonium nitrate

2) Chemical (molecular) equation

  • NH₃ (aq) + HNO₃ (aq)  → NH₄ NO₃

3) Ionization reactions

Write the dissociation of the soluble ionic compounds:

  • HNO₃ → H⁺ + NO₃⁻
  • NH₄ NO₃ → NH₄⁺ + NO₃⁻

4) Total ionic equation:

  • NH₃ (aq) +  H⁺ (aq) + NO₃⁻ (aq) →  NH₄⁺ (aq) + NO₃⁻ (aq)

5) Net ionic equation

You must cancel the spectator ions, which are those ions that are repeated in both reactant and product sides, i.e. NO₃⁻. They are name spectator because they do not participate (change) during the reaction.

  • NH₃ (aq) +  H⁺ (aq)  →  NH₄⁺ (aq)

And that is the last choice of the list.

4 0
3 years ago
What is in the space between electrons?
otez555 [7]

Answer:

The empty space between the atomic cloud of an atom and its nucleus is just that: empty space, or vacuum. ... Electrons are thus 'spread out' quite a bit in their orbits about the nucleus. In fact, the wave-functions for electrons in s-orbitals about a nucleus actually extend all the way down into the nucleus itself.

5 0
3 years ago
For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The followin
Studentka2010 [4]

Answer : The initial rate for a reaction will be 3.63\times 10^{-4}Ms^{-1}

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B+C\rightarrow D+E

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b[C]^c

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

1.2\times 10^{-4}=k(0.40)^a(0.40)^b(0.40)^c ....(1)

Expression for rate law for second observation:

3.6\times 10^{-4}=k(0.40)^a(0.40)^b(1.20)^c ....(2)

Expression for rate law for third observation:

4.8\times 10^{-4}=k(0.80)^a(0.40)^b(0.40)^c ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-4}=k(0.80)^a(0.80)^b(0.40)^c ....(4)

Dividing 1 from 2, we get:

\frac{3.6\times 10^{-4}}{1.2\times 10^{-4}}=\frac{k(0.40)^a(0.40)^b(1.20)^c}{k(0.40)^a(0.40)^b(0.40)^c}\\\\3=3^c\\c=1

Dividing 1 from 3, we get:

\frac{4.8\times 10^{-4}}{1.2\times 10^{-4}}=\frac{k(0.80)^a(0.40)^b(0.40)^c}{k(0.40)^a(0.40)^b(0.40)^c}\\\\4=2^a\\a=2

Dividing 3 from 4, we get:

\frac{4.8\times 10^{-4}}{4.8\times 10^{-4}}=\frac{k(0.80)^a(0.40)^b(0.40)^c}{k(0.80)^a(0.80)^b(0.40)^c}\\\\1=2^b\\b=0

Thus, the rate law becomes:

\text{Rate}=k[A]^2[B]^0[C]^1

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

1.2\times 10^{-4}=k(0.40)^2(0.40)^0(0.40)^1

k=1.875\times 10^{-3}M^{-2}s^{-1}

Now we have to calculate the initial rate for a reaction that starts with 0.55 M of reagent A and 0.80 M of reagents B and C.

\text{Rate}=k[A]^2[B]^0[C]^1

\text{Rate}=(1.875\times 10^{-3})\times (0.55)^2(0.80)^0(0.80)^1

\text{Rate}=3.63\times 10^{-4}Ms^{-1}

Therefore, the initial rate for a reaction will be 3.63\times 10^{-4}Ms^{-1}

4 0
3 years ago
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