Answer:
y = -x+3
Step-by-step explanation:
First find the slope
m = ( y2-y1)/(x2-x1)
= ( 2 - -3)/( 1 - 6)
( 2+3)/( 1-6)
5/ -5
-1
The slope is -1
We can use slope intercept form
y = mx+b where m is the slope and b is the y intercept
y = -x+b
Substitute a point into the equation
2 = -1 +b
Add 1 to each side
2+1 = -1+1+b
3 = b
y = -x+3
Answer:
150 students.
No
.20
3/10
Step-by-step explanation:
What you do for the first one is you take 1,500 and times it by 90%. You will get 1,350. You will then take the 1350 and minus it from 1500 to get 150 students.
The next one says that he drilled a hole that is 5/9 inches wide. He has a drill bit that is 5/6. Will the drill bit be big enough. No because 5/9 is .556 and 5/6 is .833.
For the next one all they want you to do is look at the fruit percentage and put it into a decimal which is .20.
The next one they want the fraction that represents 30% which is 3/10.
Given:
Polynomial is 
.
To find:
The sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form.
Solution:
The sum of given polynomial and the square of the binomial (x-8) is
![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
On combining like terms, we get
Therefore, the sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form is 
.
Answer:
Step-by-step explanation:
Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.
Problem 1:
(x²)/4 +y²= 1
y= x+1
*substitute for y*
Now we have a one-variable equation we can solve-
x²/4 + (x+1)² = 1
x²/4 + (x+1)(x+1)= 1
x²/4 + x²+2x+1= 1
*subtract 1 from both sides to set equal to 0*
x²/4 +x^2+2x=0
x²/4 can also be 1/4 * x²
1/4 * x² +1*x² +2x = 0
*combine like terms*
5/4 * x^2+2x+ 0 =0
now, you can use the quadratic equation to solve for x
a= 5/4
b= 2
c=0
the syntax on this will be rough, but I'll do my best...
x= (-b ± √(b²-4ac))/(2a)
x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))
x= (-2 ±√(4-0))/(2.5)
x= (-2±2)/2.5
x will have 2 answers because of ±
x= 0 or x= 1.6
now plug that back into one of the equations and solve.
y= 0+1 = 1
y= 1.6+1= 2.6
Hopefully this explanation was enough to help you solve problem 2.
Problem 2:
x² + y² -16y +39= 0
y²- x² -9= 0
