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alexgriva [62]
3 years ago
15

Maria finishes ¾ of the race in 6 hours. How long was the entire race?

Mathematics
1 answer:
GuDViN [60]3 years ago
6 0

Answer:

We are asked to find the duration of entire race. As Rachel finished of the race in 6 hours, so of x will be equal to 6. Therefore, the duration of entire race was 8 hours.

( i looked this up but that is the answer i dont take any credit for this answer)  

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Twenty percent of the 640 pitches Kendall threw last year were strikes. Which table can be used to find the number of strikes sh
Ksju [112]

Answer:

1 out of every 5 throws were strikes.

Step-by-step explanation:

20% is one fifth of 100%.

5 0
3 years ago
Read 2 more answers
Please help me im stuck on this question​
STALIN [3.7K]

Answer:

78.0 kilo

Step-by-step explanation:

85.8- 93.6= 7.8

101.4-93.6= 7.8

85.8-7.8 = 78.0 kilo

6 0
3 years ago
A Gallup Poll in July 2015 found that 26% of the 675 coffee drinkers in the sample said they were addicted to coffee. Gallup ann
emmasim [6.3K]

Answer:

The 95% confidence interval for the percent of all coffee drinkers who would say they are addicted to coffee is between 21% and 31%.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

A confidence interval has two bounds, the lower and the upper

Lower bound:

\pi - M

Upper bound:

\pi + M

In this problem, we have that:

\pi = 0.26, M = 0.05

Lower bound:

\pi - M = 0.26 - 0.05 = 0.21

Upper bound:

\pi + M = 0.26 + 0.05 = 0.31

The 95% confidence interval for the percent of all coffee drinkers who would say they are addicted to coffee is between 21% and 31%.

4 0
3 years ago
If the value of third order determinant is 11. Then what is the value of the determinant formed by its cofactors.
nordsb [41]

Answer:

146.41

Step-by-step explanation:

third order determinant = determinant of 3×3 matrix A

given ∣A∣=11

det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)

=det(adjacent of A)

{det (cofactor matrix of A)}  ^2  = {det (adjacent of A)} ^2

 

(Using for an n×n det (cofactor matrix of A)=det (A)^n−1 )

we get

det (cofactor matrix of A)^2  = {det(A)  ^3−1 }^2

 

=(11)^2×2  = 11^4

 =146.41

5 0
3 years ago
he coordinate grid shows the graph of four equations: A coordinate grid is shown from negative 12 to positive 12 on the x axis a
denis23 [38]

The set of equation that is known to have 5 and 0 as solutions is A and B.

<h3>How to solve for the system of equations.</h3>

From the graph that we have here in this question, we are supposed to identify the equations that have this point.

We can do this by tracing the lines in order to locate 5 and 0 on the grid.

When we trace the bine that has 5 and 0, We would find out that it is traceable to A and B.

Read more on graphs here:

brainly.com/question/10465970

#SPJ1

6 0
2 years ago
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