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baherus [9]
1 year ago
9

Classify each polynomial according to its degree and type. Look at the screenshot below!

Mathematics
1 answer:
Ahat [919]1 year ago
8 0

Answer:

                  Monomial    Binominal     Trimoninal

Degree 1:        -9x               x + 6

Degree 2:       -4x^{2}             4x^{2} -x       x -3x^{2} + 1

Degree 3:        4x^{3}            5 - 2x^{3}         3x^{2}  + 3x^{3} -10

Step-by-step explanation:

I do not know how to explain how I got to this answer, but here is the answer.

You might be interested in
Which expression is equivalent to the given expression?
PSYCHO15rus [73]

Answer:

-5(y - 3)(y - 7)

Step-by-step explanation:

Factor -5 out of all 3 terms:

-5(y^2 - 10y + 21)

Continue the factoring:

-5(y - 3)(y - 7)

Note:  when answer choices are given, kindly share them.  Thank you.

6 0
3 years ago
Perform the indicated row operations, then write the new matrix.
Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]

Operations:

2R_1 + R_2 ->R_2

-3R_1 +R_3 ->R_3

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]

Step-by-step explanation:

The first operation:

2R_1 + R_2 ->R_2

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]

Multiply by 2

2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]

Add to row 2 elements are: \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]

\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]

\left[\begin{array}{ccc}0&5&7|1\end{array}\right]

The second operation:

-3R_1 +R_3 ->R_3

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]

Multiply by -3

-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]

Add to row 2 elements are: \left[\begin{array}{ccc}3&2&4|1\end{array}\right]

\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]

\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]

Hence, the new matrix is:

\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]

3 0
3 years ago
Read 2 more answers
9x + 3y = 39
stiks02 [169]

Answer:

I don't know

Step-by-step explanation:

thanks for the points

7 0
2 years ago
AT&T would like to test the hypothesis that the proportion of 18- to 34-year-old Americans that own a cell phone is less tha
Vera_Pavlovna [14]

Answer:

The null and alternative hypothesis can be written as:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of 18- to 34-year-old Americans that own a cell phone is less than the proportion of 35- to 49-year-old Americans.

This claim will be reflected in the alternnative hypothesis, that will state that the population proportion 1 (18 to 34) is significantly smaller than the population proportion 2 (35 to 49).

On the contrary, the null hypothesis will state that the population proportion 1 is ot significantly smaller than the population proportion 2.

Then, the null and alternative hypothesis can be written as:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0

The significance level is assumed to be 0.05.

The sample 1, of size n1=200 has a proportion of p1=0.63.

p_1=X_1/n_1=126/200=0.63

The sample 2, of size n2=175 has a proportion of p2=0.68.

p_2=X_2/n_2=119/175=0.68

The difference between proportions is (p1-p2)=-0.05.

p_d=p_1-p_2=0.63-0.68=-0.05

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{126+119}{200+175}=\dfrac{245}{375}=0.653

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.653*0.347}{200}+\dfrac{0.653*0.347}{175}}\\\\\\s_{p1-p2}=\sqrt{0.001132+0.001294}=\sqrt{0.002427}=0.049

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.05-0}{0.049}=\dfrac{-0.05}{0.049}=-1.01

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

\text{P-value}=P(z

As the P-value (0.1554) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the proportion of 18- to 34-year-old Americans that own a cell phone is less than the proportion of 35- to 49-year-old Americans.

5 0
3 years ago
HELPPPP!!!!!<br><br> Is (how many slices of pizza can you eat) a statistical question?
cluponka [151]

Answer:

no

Step-by-step explanation: because a statistical question means tthat you can find proof for example how many slices of pizza did i eat out 12? that you can answer

3 0
2 years ago
Read 2 more answers
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