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-Dominant- [34]
3 years ago
13

Find the largest factor of 2520 that is not divisible by 6.

Mathematics
2 answers:
Vesna [10]3 years ago
6 0
80 ok because it has that
son4ous [18]3 years ago
5 0
The largest factor that is not divisible by 6 is 315.
You might be interested in
What are the factors of 2x + 3x - 54? Select two options
tiny-mole [99]

Answer:

The answer: The factors are (2x-9) and (x+6).

The Problem:

Factor 2x^2+3x-54

Step-by-step explanation:

So I'm going to do trial factors using the choices to aid me.

Factored form for this problem if it exist will be in the form:

(mx+n)(kx+p).

In general this is what it would look like if we factored any quadratic in terms of x (given the quadratic is not prime but technically you could factor even over the complex numbers).

Let's look at:

(mx+n)(kx+p)

We want to choose k \text{ and } m such that when you multiply them you get 2.  Well those would have to be 2 and 1.

(2x+n)(x+p)

we want to choose n \text{ and } p such that when you multiply them you get -54. Based on the choices we want to get with -9 and 6, or 9 and -6. We don't know the order we want to choose it in either.

For example which of these would work:

(2x-6)(x+9)

(2x+6)(x-9)

(2x-9)(x+6)

(2x+9)(x-6)

We are going to consider only the outer and inner of FOIL since we already know the first times the first is 2x^2 and the last times the last is -54.

Let's test the first one:

(2x-6)(x+9)

Outer:  2x(9)=18x

Inner: -6(x)=-6x

------------------------ADD!

18x-6x=12x

The first choice did not give us the middle term 3x.

Trying the second one would give us the opposite since they are in the same form as previous just the + and - are switched.

Let's look at the third one:

(2x-9)(x+6)

Outer: 2x(6)=12x

Inner: -9(x)=-9x

--------------------------ADD!

12x-9x=3x

This is the winner.

The answer: The factors are (2x-9) and (x+6).

7 0
3 years ago
Read 2 more answers
You have some money in your wallet. You don't know the exact amount, but you think you have 60 dollars give or take 15 dollars.
Karolina [17]

Answer:

The least amount is 75 dollars.

The biggest amount is 125 dollars

Step-by-step explanation:

The absolute value function will help us determine a  range of possible values since we do not know the exact amount of money.

Defining the function.

Let x be the exact amount of money in my pocket, we can define the equation

And we know that the difference between the exact amount of money with 100 dollars must be either 25 dollars more than what we estimated, or 25 dollars less than the estimation.  So we can write:

We have a difference inside an absolute value, since we know the difference must be either +25 or -25.

Solving for x

Using the definition of absolute value we have

So if the inside of the absolute value is positive we have the first line of the piece-wise function, that is

Solving for x give us

If the inside of the absolute value is negative we have to use the second line of the piece-wise function definition

Solving for x give us

So the least amount of money in my pocket is 75 dollars and the biggest amount is 125 dollars.

6 0
2 years ago
Will give brainliest
Ostrovityanka [42]

\displaystyle\\\sum_{n=1}^7(4n+2)

6 0
3 years ago
9,513 rounded to the nearest thousand
zhenek [66]
9513 rounded to the nearest thousandth is 10,000.

I hope that helped! :>
4 0
3 years ago
Read 2 more answers
Check out attachment:) I don't understand how do you find out the length ?? pls help with explanation thx
hjlf

Answer:

x=3.89

Step-by-step explanation:

I'll go in depth for you.

Before we figure out what we do, let understand what we know about this triangle.

  • We know that both triangles have a angle that measure 27°.
  • We also know EH=5
  • FG=9
  • ZG=7
  • We need to know how to find EZ

Notice how line EG and HF intersect at Angle Z. We know that if two lines intersect at an angle, it form angles called vertical angles. This means that the two angles that are vertical to each other are congruent.

This means that angle Z in both triangles both measure the same.

Now since both triangles have 2 congruent corresponding angles, we can say that the <em>Triangles</em><em> </em><em>are</em><em> </em><em>Similar</em><em> </em><em>due</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>Angle-Angle</em><em> </em><em>Postulate</em><em>.</em>

<em>"</em><em>If</em><em> </em><em>two</em><em> </em><em> </em><em>corresponding</em><em> </em><em>angles</em><em> </em><em>of</em><em> </em><em>two</em><em> </em><em>triangles</em><em> </em><em>are</em><em> </em><em>congruent</em><em>,</em><em> </em><em>then</em><em> </em><em>the</em><em> </em><em>two</em><em> </em><em>triangles</em><em> </em><em>are</em><em> </em><em>similar</em><em>.</em><em>"</em>

<em>What</em><em> </em><em>is</em><em> </em><em>mean</em><em> </em><em>when</em><em> </em><em>Triangles</em><em> </em><em>are</em><em> </em><em>similar</em><em>?</em><em> </em>

<em>It</em><em> </em><em>means</em><em> </em><em>that</em><em> </em><em>the</em><em> </em><em>similar</em><em> </em><em>triangles</em><em> </em><em>corresponding</em><em> </em><em>angles</em><em> </em><em>are</em><em> </em><em>equal</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>their</em><em> </em><em>sides</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>proportion</em><em>.</em>

<em>The</em><em> </em><em>corresponding</em><em> </em><em>sides</em><em> </em><em>are</em><em> </em>

<em>EH</em><em> </em><em>and</em><em> </em><em>GF</em>

<em>EZ</em><em> </em><em>and</em><em> </em><em>ZG</em>

<em>HZ</em><em> </em><em>and</em><em> </em><em>HF</em><em>.</em>

<em>Our</em><em> </em><em>proportion</em><em> </em><em>formula</em><em> </em><em>for</em><em> </em><em>similar</em><em> </em><em>triangle</em><em>s</em><em> </em><em>is</em><em> </em>

<em>Any</em><em> </em><em>two</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>triangle</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>each</em><em> </em><em>other</em><em> </em><em>must</em><em> </em><em>equal</em><em> </em><em>the</em><em> </em><em>two</em><em> </em><em>corresponding</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>second</em><em> </em><em>triangles</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>each</em><em> </em><em>other</em><em> </em><em>respectively</em><em>.</em>

<em>We</em><em> </em><em>know</em><em> </em><em>FG</em><em> </em><em>and</em><em> </em><em>ZG</em><em> </em><em>so</em><em> </em><em>let</em><em> </em><em>set</em><em> </em><em>up</em><em> </em><em>our</em><em> </em><em>first</em><em> </em><em>fraction</em>

<em>\frac{fg}{zg}</em>

<em>The</em><em> </em><em>corresponding</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>both</em><em> </em><em>are</em><em> </em>

  • <em>EH</em><em> </em><em>and</em><em> </em><em>EZ</em><em> </em><em>respectively</em><em> </em><em> </em><em>so</em><em> </em><em>our</em><em> </em><em>proportion</em><em> </em><em> </em><em>looks</em><em> </em><em>like</em>
  • <em>\frac{fg}{zg}  =  \frac{eh}{ez}</em>
  • <em>Plug</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>for</em><em> </em><em>each</em><em>.</em><em> </em><em>Let</em><em> </em><em>x</em><em> </em><em>represent</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>EZ</em>
  • <em>\frac{9}{7}  =  \frac{5}{x}</em>
  • <em>Cross</em><em> </em><em>Multiply</em>
  • <em>9x = 35</em>
  • <em>x = 3 \frac{8}{9}  = 3.89</em>
  • <em>So</em><em> </em><em>x</em><em>=</em><em>3</em><em>.</em><em>8</em><em>9</em>
3 0
3 years ago
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