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Vanyuwa [196]
2 years ago
6

27 Solve for x to the nearest tenth: x² + x - 5 = 0.

Mathematics
1 answer:
Anestetic [448]2 years ago
4 0

Answer:

Step-by-step explanation:

We can use the quadratic formula to get the answer to this

Quadratic Formula: -b +- √b² - 4ac/2a

Once we input A, B, and C into this, and solve any multiplication, we get

x = -1  +- √1 + 20/2

We divide by 2a, which 2a = 2.

-0.5 +- 10.5.

these are the following values of x:

x = 10

x = 11

Pretty sure this is it, hope it helps!

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Read 2 more answers
what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible
zheka24 [161]

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0
2 years ago
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