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borishaifa [10]
3 years ago
5

What is the least common denominator of 5/6 and 3/4?

Mathematics
1 answer:
ololo11 [35]3 years ago
5 0
This lcd is also twelve
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Take a quadratic equation in standard form:
If there exists a sum of two numbers that equal b, whose addends produce a product that equals c. You can rewrite the quadratic as a product of two binomials.


For example take
When thought through throughly, -5 had addends, -2 and -3 that produce 6 when multiplied
Thus, we can rewrite the quadratic as.
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8y + 6 - 15y + 5 - 3
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Step-by-step explanation: im not really sure what it is but if you are working from this probplem do pemdas-

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An Explanation Or Answer?
Delicious77 [7]
<span>4x + 1 ≥ 5
x</span><span>≥1
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3 years ago
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Find the area of the figure shown below and choose the appropriate result.
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Step-by-step explanation:

14

8 0
3 years ago
The mean one-way commute to work in Chowchilla is 7 minutes. The standard deviation is 2.4 minutes, and the population is normal
adell [148]

Answer:

The answer is below

Step-by-step explanation:

Given that:

The mean (μ) one-way commute to work in Chowchilla is 7 minutes. The standard deviation (σ) is 2.4 minutes.

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z=\frac{x-\mu}{\sigma}

a) For x < 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

From normal distribution table,  P(x < 2) = P(z < -2.08) = 0.0188 = 1.88%

b) For x = 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

For x = 11:

z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67

From normal distribution table, P(2 < x < 11) = P(-2.08 < z < 1.67 ) = P(z < 1.67) - P(z < -2.08) = 0.9525 - 0.0188 = 0.9337  

c) For x = 11:

z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67

From normal distribution table,  P(x < 11) = P(z < 1.67) = 0.9525

d) For x = 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

For x = 5:

z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83

From normal distribution table, P(2 < x < 5) = P(-2.08 < z < -0.83 ) = P(z < -0.83) - P(z < -2.08) =  0.2033- 0.0188 = 0.1845  

e) For x = 5:

z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83

From normal distribution table,  P(x < 5) = P(z < -0.83) = 0.2033

8 0
4 years ago
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