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tatyana61 [14]
2 years ago
15

Use Boyle's Law to interpret the following problem and then select the correct answer below.

Chemistry
1 answer:
FromTheMoon [43]2 years ago
4 0

The pressure of the compressed tank that was initially filled with hydrogen gas and has a pressure of 100kPa is pressure in the 250mL tank increases.

<h3>What is Boyle's law?</h3>

Boyle's law states that the observation that the pressure of an ideal gas is inversely proportional to its volume at constant temperature.

According to this question, a 1 L compressed tank is filled with hydrogen gas and has a pressure of 100kPa.

If all of the hydrogen gas is removed from the tank and pumped into a 250mL tank, which is smaller in volume, the pressure in the 250mL tank increases.

Learn more about pressure at: brainly.com/question/12971272

#SPJ1

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D = m / V


It even gives you the density of gold in the problem. Major hint. Once you know the volume (using V = m / D) then you can calculate the height (thickness) from the equation...


V = L x W x H

Volume = Length x Width x Height


start by converting 200.0 mg into grams

1000 mg = 1 g

200. mg x (1 g / 10^3 mg) = 0.200 g


V = m / D

V = 0.200 g / (19.32 g/cm^3)

V = 0.01035 cm^3


Convert 2.4 ft and 1 ft to cm

2.4 ft x (12 in / 1 ft) x (2.54 cm / 1 in) = 73.15 cm

1 ft = 30.48 cm


Compute the height (thickness)

V = LxWxH

H = V / LW = 0.01035 cm^3 / 73.15 cm / 30.48 cm

H = 4.64 x 10^-6 cm


Convert to nanometers

4.64 x 10^-6 cm x (1 m / 100 cm) x (10^9 nm / 1 m) = 46.4 nm


Knowing the atomic radius of gold, I might have asked my students for the minimum number of gold atoms in this thickness of gold. This would assume that the gold atoms are all in a row. This would give the minimum number of gold atoms.


Atomic radius gold = 174 pm

Diameter = 348 pm


46.4 nm x (1 m / 10^9 nm) x (10^12 pm / 1 m) x (1 Au atom / 248 pm) = 133 atoms of gold


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4 years ago
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