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serious [3.7K]
3 years ago
9

Ammonium hydrogen sulfide NH4HS(s) decomposes on heating according to the reaction NH4HS(s) ↔ NH3(g) + H2S(g) At 25 °C the equil

ibrium cnstant of the reaction is Kp = 0.11. What is the total pressure at that temperature in a flask that was initially partially filled with a sizeable amount of NH4HS(s)?
Chemistry
2 answers:
yan [13]3 years ago
3 0

Answer:

0.66atm

Explanation:

Based on the reaction:

NH₄HS(s) ↔ NH₃(g) + H₂S(g)

The equilibrium constant, Kp, is defined as:

Kp = 0.11 = P_{NH_3} P_{H_2S}

As moles of gas produced for NH₃(g) and H₂S(g) are the same, it is possible to write:

0.11 = P_{NH_3}^2

0.33 = P_{NH_3}

That means pressure of NH₃(g) is 0.33atm and H₂S(g) is, also, 0.33atm. Thus, total pressure is:

0.33atm×2 = <em>0.66atm</em>

skelet666 [1.2K]3 years ago
3 0

Answer:

Its B

Explanation:

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-70°C

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Explanation:

Completing the statements:

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5 0
3 years ago
Read 2 more answers
What is the percent yield of a reaction in which 200. g of phosphorus trichloride reacts with excess water to form 91.0 g of hcl
Snowcat [4.5K]
Answer is: <span>yield of a reaction is 56,4%.
</span>Chemical reaction: PCl₃ + 3H₂O → 3HCl + H₃PO₃.
m(PCl₃) = 200 g.
m(HCl) = 91,0 g.
n(PCl₃) = m(PCl₃) ÷ M(PCl₃).
n(PCl₃) = 200 g ÷ 137,33 g/mol.
n(PCl₃) = 1,46 mol.
n(HCl) = m(HCl) ÷ M(HCl).
n(HCl) = 91 g ÷ 36,45 g/mol.
n(HCl) = 2,47 mol.
From reaction: n(PCl₃) : n(HCl) = 1 : 3.
n(HCl) = 1,46 mol · 3 = 4,38 mol.
Yield of reaction: 2,47 mol ÷ 4,38 mol · 100% = 56,4%.
4 0
3 years ago
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Look at picture please
Tom [10]

Answer:

Keep temperature constant and increase the pressure of the reaction. The rate of reaction increases.

Explanation:

First of all, the question is asking us to design an experiment to investigate the effect of pressure on the rate of reaction hence the pressure can not be held constant since it is the variable under investigation. This eliminates the first option.

Secondly, increasing the pressure of the reaction means that particles of the gas collide more frequently leading to a greater number of effective collisions and a consequent increase in the rate of reaction according to the collision theory.

Hence the answer above.

3 0
3 years ago
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Arada [10]
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Sedaia [141]
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3 years ago
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