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Paul [167]
3 years ago
10

Round 23.455 cm into 4 significant figures

Chemistry
2 answers:
seraphim [82]3 years ago
4 0
It would be 23.46, since the next number is a 5 so we can round up.

Significant figures are:
ANY number that is not 0
Any 0 between two nonzero digits
Any 0 following a decimal (i.e 1.50)
cluponka [151]3 years ago
4 0

Answer:

23.46

Explanation:

Significant figures are the number of digits or the numbers that contribute to the actual value of a measurement.

Some of the rules to check the number of significant figures are:

- All non-zero digits are always significant

-Zeros in between numbers are significant

-Leading zeros after decimal are not significant

-Trailing zeros after decimal are significant

-If the final digit after decimal is greater than or equal to 5, it can be rounded up to the next higher number

The given value is:

23.455 it has 5 significant figures

Rounding up (since the last digit = 5) to 4 significant figures gives:

23.46

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Answer:

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Hope this helps, thank you :) and I am not sure about magnitude I think you can that since there is greater force on the right side, there is more magnitude there.

4 0
3 years ago
Which type of covalent bond is the least stable?
sergejj [24]

Hello ^^

Answer:

D.Triple Bonds

Explanation:

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8 0
3 years ago
Read 2 more answers
The graph given below shows the motion of four runners P, Q, R, and S in a 5 km marathon.
wel

Answer:-

As we can see from the graphical data,

The distance covered by all the four runners is the same 5 km.

Among the four athletes, Athlete P covers the distance in under three hours.

It is the minimum time taken among the four athletes.

Thus Athlete P covers the 5 km distance in the minimum amount of time.

We know that speed = \frac{Distance}{Time}

Since time taken for P is minimum, his speed is the maximum. P ran the fastest.

Time taken by Q = 4.5 hours.

Speed of Q = \frac{Distance}{Time taken by Q}

                     = \frac{5km}{4.5hour}

                    = 1.1 km/ hr

Time taken by R = 6 hours.

Speed of R = \frac{Distance}{Time taken by R}

                     = \frac{5km}{6hour}

                    = 0.8 km/ hr

3 0
3 years ago
How many grams of water are theoretically produced for the following reaction given we have 2.6 moles of HCl and 1.4 moles of Ca
leva [86]

Answer:

The answer to your question is: 6.8 g of water

Explanation:

Data

2.6 moles of HCl

1.4 moles of Ca(OH)2

                           2HCl     +     Ca(OH)2    →        2H2O    +      CaCl2

MW                   2(36.5)               74                       36 g               111 g

                          73g                

                            1 mol of HCl ----------------  36.5 g

                           2.6 mol           --------------    x

                              x = (2.6 x 36.5) / 1   = 94.9 g

                           1 mol of Ca(OH)2 --------------   74 g

                         1.4 mol                  ---------------   x

                            x = (1.4 x 74) / 1  = 103.6 g

Grams of water

                        73 g of HCl ------------------   36g of H2O

                        94.9 g        -------------------    x

                     x = (94.9 x 36) / 73 = 46.8 g of water

6 0
3 years ago
Sodium phosphate and calcium chloride react to form sodium chloride and calcium phosphate. If you have 379.4 grams of calcium ch
barxatty [35]

Answer: 353.6 g.


Explanation:


1) Word equation (given)

Sodium phosphate + calcium choride → sodium chloride + calcium phosphate


2) Balanced chemical equation

2 Na₃PO₄ +3 CaCl₂ → 6 NaCl + Ca₃(PO4)₂


3) Mole ratio

2 moles Na₃PO₄ : 3 moles CaCl₂ :  6 moles NaCl : 1 mole Ca₃(PO4)₂


4)  Formula to convert grams to moles

number of moles = mass in grams / molar mass


5) Number of moles of limiting reactant

a) mass in grams = 379.4 g CaCl₂

b) molar mass CaCl₂ = 110.98 g/mol

c) number of moles CaCl₂ = 379.4 g / 110.98 g/mol = 3.419 moles


6) Theoretical yield of Ca₃(PO4)₂

    3 moles CaCl₂ / 1 mole Ca₃(PO4)₂ = 3.419 moles CaCl₂ / x ⇒

    x = 3.419 × 1 / 3 = 1.140 moles Ca₃(PO4)₂


7) Convert 1.140 moles Ca₃(PO4)₂

a) molar mass Ca₃(PO4)₂ = 310.1767 g/mol

b) mass in grams = number of moles × molar mass = 1.140 moles × 310.1767 g/mol = 353.6 g ← answer.

7 0
3 years ago
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