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galina1969 [7]
3 years ago
11

Consider the scatter plot.

Mathematics
1 answer:
AnnZ [28]3 years ago
7 0
1)Negative Association;False
2)True
pls dont kill me if im wrong
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. Use the statistical features of your calculator to find the mean and the standard deviation to the nearest tenth of a data set
uysha [10]

Answer:

Mean = 1.9

Standard deviation = 0.6

Step-by-step explanation:

The Mean is calculate by the formula:

Mean = \frac{\text{Sum of all the observation}}{\text{Total number of observation}}

⇒ Mean = \frac{24.9+24.7+24.7+23.4+27.9}{5} = 1.85

Thus Mean to the nearest tenth is 1.9

Standard Deviation is the square root of sum of square of the distance of observation from the mean.  

Standard deviation(\sigma) = \sqrt{\frac{1}{n}\sum_{i=1}^{n}{(x_{i}-\bar{x})^{2}} }

where, \bar{x} is mean of the distribution.

Putting all values in the formula, We get

Standard Deviation = 0.597 ≈ 0.6

6 0
3 years ago
Beth hiked 4 3/10 Jose hiked 3 6/10 how much farther in miles did Beth hike than Jose
aleksandrvk [35]

Answer:

7/10

0.70

Step-by-step explanation:

BETH- 4.30

JOSE- 3.60

4.30 - 3.60 = .70

.70 = 7/10

3 0
3 years ago
Write the congruency statement for the triangles. _______In triangles MNO and JKL, there are two congruent sides and included an
mafiozo [28]

Answer:

ΔJKL ≅ ΔMNO by SAS

Step-by-step explanation:

The question is incomplete, the question is as following:

ΔMNO is shown.

Which Δ below can be shown to be congruent to ΔMNO with only the given information?

Name the postulate that justifies your answer (SAS, AAS, HL, ASA or SSS).

Write the congruency statement for the triangles.

And see the attached figure which represent ΔMNO

==========================================================

Check the given options to see which triangle from the option will be congruent to ΔMNO

1. In triangles MNO and ABC, there are two congruent sides and non-included angle - which mean (angle - side - side)

The (angle - side - side) Postulate does not exist because an angle and two sides does not guarantee that two triangles are congruent.

2. In triangles MNO and DEF, there are two congruent sides - there is not enough information

3. In triangles MNO and GHI, there are three congruent angles - which mean AAA (angle - angle - angle)

The AAA Postulate does not exist because an angle and two sides does not guarantee that two triangles are congruent. This postulate is used to prove the similarity between the triangles.

4. In triangles MNO and JKL, there are two congruent sides and included angle - SAS (side - angle - side)

MN ≅ JK , MO ≅ JL , ∠M ≅ ∠J

5 0
3 years ago
Suppose each edge of the cube shown in the figure is 10 inches long. Find the sine and cosine of the angle formed by diagonals D
tatiyna

Check the picture below.

sin(EDG )=\cfrac{\stackrel{opposite}{10}}{\underset{hypotenuse}{10\sqrt{3}}}\implies sin(EDG )=\cfrac{1}{\sqrt{3}}\implies sin(EDG )=\cfrac{1}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{sin(EDG )=\cfrac{\sqrt{3}}{\sqrt{3^2}}\implies sin(EDG )=\cfrac{\sqrt{3}}{3}} \\\\[-0.35em] ~\dotfill

cos(EDG )=\cfrac{\stackrel{adjacent}{10\sqrt{2}}}{\underset{hypotenuse}{10\sqrt{3}}}\implies cos(EDG )=\cfrac{\sqrt{2}}{\sqrt{3}}\implies cos(EDG )=\cfrac{\sqrt{2}}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{cos(EDG )=\cfrac{\sqrt{6}}{\sqrt{3^2}}\implies cos(EDG )=\cfrac{\sqrt{6}}{3}}

4 0
2 years ago
Question 1: The water level in a tank can be modeled by the function h(t)=4cos(+)+10, where t is the number of hours
Amanda [17]

Answer:

Question 1: The hours that will pass between two consecutive times, when the water is at its maximum height is π hours

Question 2: Sin of the angle is -0.8

Step-by-step explanation:

Question 1: Here we have h(t) = 4·cos(t) + 10

The maximum water level can be found by differentiating h(t) and equating the result to zero as follows;

\frac{\mathrm{d}  h(t)}{\mathrm{d} t} = \frac{\mathrm{d} \left (4cos(t) + 10  \right )}{\mathrm{d} t} = 0

\frac{\mathrm{d}  h(t)}{\mathrm{d} t} = - 4 \times sin(t) = 0

∴ sin(t) = 0

t = 0, π, 2π

Therefore, the hours that will pass between two consecutive times, when the water is at its maximum height = π hours.

Question 2:

B = (3, -4)

Equation of circle = x² + y² = 25

Here we have

Distance moved along x coordinate = 3

Distance moved along y coordinate = -4

Therefore, we have;

Tan \theta = \frac{Distance \ moved \ along \ y \ coordinate}{Distance \ moved \ along \ x \ coordinate} = \frac{-4}{3}

\therefore \theta = Tan^{-1}(\frac{-4}{3}) = -53.13^{\circ}

Sinθ = sin(-53.13) = -0.799≈ -0.8.

5 0
3 years ago
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