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frozen [14]
2 years ago
7

If a and b are real numbers and a>0 and b>0 , then ab ___0

Mathematics
1 answer:
Pepsi [2]2 years ago
4 0

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Answer:  \textsf{ab} > \textsf{0}

-------------------------------------------------------------------------------------------------------------

Given: \textsf{a} > \textsf{0 and b} > \textsf{0}

Find:  \textsf{ab } \_\_\_ \textsf{ 0}

Solution: Since we know both a and b are positive this means that if they are multiplied against each other they would produce another positive. Therefore, this would cause the statement to be ab > 0.

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Answer:

  (5, 6) is (h, k)

Step-by-step explanation:

Vertex form is an instance of the transformation of parent function f(x) = x². It is vertically scaled by a factor of 'a', and translated so the vertex is point (h, k). That is, the transformed vertex is h units right and k units up from that of the parent function (0, 0).

Parent:

  f(x) = x^2

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When you compare the form to your specific instance, you need to pay attention to what it is that you're comparing. As the attachment shows, ...

  • a = 2
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Hence the vertex is (h, k) = (5, 6). The second attachment shows this on a graph.

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