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aniked [119]
3 years ago
6

A classroom has 2 bookcases that weigh 117 pounds altogether. If they all weigh the same amount, how much does each bookcase wei

gh?
Mathematics
2 answers:
Lapatulllka [165]3 years ago
6 0

Answer:

58.5 pounds each.

Step-by-step explanation:

If two bookcases weigh 117 pounds and each weighs the same amount, each bookcase must weigh half of the total weight. 117/2 equals 58.5.

Roman55 [17]3 years ago
4 0

Answer:

They weigh 58.5 pounds each.

Step-by-step explanation:

You just have to dived the total amount by the amount of thing. So you would didvid 117 by 2 which equals 58.5 pounds.

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According to the school survey, 12% of the students at rock wood junior high school speak Spanish. There are 36 students at the
exis [7]

Answer:

They surveyed 300 students

Step-by-step explanation:

In order to find this, take the number who said they speak Spanish and then divide that number by the percentage.

36 students / 12% = 300 total students.

6 0
3 years ago
Solve for -6+3x=x-2+4x
Iteru [2.4K]

Answer:

x= -2

Step-by-step explanation: If you feel skeptical about my answer, then you should plug -2 back into the equation to check if it's correct. And it's correct for me when I did it.

7 0
4 years ago
Given that an American is a male, what is the probability that he prefers name-brand milk? b. Given that an American is a female
Evgesh-ka [11]

Answer:

a) 0.280

b) 0.300

c) No, preference is not independent of gender. Since the P(N) (0.29) is not equal to P(N|M) (0.28) and/or P(N|F) (0.30), the preference and gender are not completely, statistically independent. It's very close though.

Step-by-step explanation:

Let the probability that the somebody surveyed is a male be P(M)

Let the probability that somebody surveyed is female be P(F)

Let the probability that somebody surveyed picked the name-brand milk be P(N)

Let the probability that somebody surveyed picked the store-brand milk be P(St)

Let the probability that somebody surveyed picked the something else be P(So)

a) Given that an American is a male, what is the probability that he prefers name-brand milk = P(N|M) = 319/1138 = 0.280

b) Given that an American is a female, what is the probability that she prefers name-brand milk = P(N|F) = 341/1138 = 0.300

c) To investigate if the preference and gender are independent or not, we need the P(N)

P(N) = probability that an average an Average American (male or female) will prefer a nam-brand milk = 660/2276 = 0.290.

Since the P(N) (0.29) is not equal to P(N|M) (0.28) and/or P(N|F) (0.30), the preference and gender are not statistically independent. It's very close though.

3 0
3 years ago
Simplify. (Assume all variables represent positive real numbers). Leave answer in radical form.
Flauer [41]

Answer:

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

Step-by-step explanation:

Given

\sqrt{128a^{6}b^{13}}

Required

Solve

\sqrt{128a^{6}b^{13}}

The expression can be split to:

\sqrt{128a^{6}b^{13}} = \sqrt{128} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64 * 2} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12 + 1}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12}} * \sqrt{b}

So, we have:

\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{6/2} * b^{12/2} * \sqrt{b}

\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{3} * b^{6} * \sqrt{b}

Rewrite as:

\sqrt{128a^{6}b^{13}} = 8 * a^{3} * b^{6}* \sqrt{2}  * \sqrt{b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6}* \sqrt{2b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

5 0
3 years ago
2. Suppose mZTOK = 49° .
vesna_86 [32]

Answer:

Part A: 41

Part B: 131

Step-by-step explanation:

PART A: Since a complementary angle is one that adds up to a total of 90 degrees the complement of 49 should be 41

90-49=41

PART B: Since a supplementary angle is one that adds up to a total of 180 degrees the supplement of 49 should be 131

180-49=131

Hope this helps!!! :)

6 0
3 years ago
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