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Stella [2.4K]
3 years ago
8

Evaluate the expression when x-6

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
7 0
If x=6 then that’s 5(6) =30+3 =33 and if your dividing 33/3 makes 11
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ONLY ANSWER IF YK IT ILL GIVE THE CORRECT ANSWER BRAINLIEST
Olin [163]

Answer:

  9 units

Step-by-step explanation:

If you assume the solution is an integer, then you are looking for factors of 27 that differ by 6. You don't have to look far:

  27 = 1×27 = 3×9

If the length is 9 units and the width is 3 units, the width is equal to the length minus 6 units.

The length is 9 units.

_____

<em>Alternate solutions</em>

You can write an equation for the area using L to represent the length. The area is the product of length and width, so is ...

  A = LW

  27 = L(L-6) = L^2 -6L

You can "complete the square" by adding the square of half the L coefficient:

  27 +3^2 = L^2 -6L +3^2

  36 = (L -3)^2 . . . . . simplify a bit

  6 = L -3 . . . . . . . . . positive square root

  9 = L . . . . . . . . . . . . add 3

The length is 9 units.

__

You can also put the quadratic equation into standard form:

  L^2 -6L -27 = 0

To factor this, you're looking for factors of -27 that have a sum of -6. From above, we know these are -9 and +3. So the factorization is ...

  (L -9)(L +3) = 0

The solutions are the values of L that make these factors be zero:

  L -9 = 0   ⇒   L = 9

  L +3 = 0   ⇒   L = -3

Only the positive solution is useful as a measure of length. The length is 9 units.

3 0
3 years ago
Giải phương trình:<br> sin*2x+sinxx.cox=1/2
creativ13 [48]

Answer:

x = 9.47 degrees  ( in first quadrant.

Step-by-step explanation:

sin2x + sinx cos x = 1/2

Now sinx cos x = 1/2sin2x so:

3/2sin2x = 1/2

sin2x = 1/2 / 3/2

sin2x = 1/2 * 2/3 = 1/3

2x = arcsin 1/3 = 19.47 degrees

x = 9.74 degrees to nearest hundredth.

6 0
2 years ago
What the answer now to the question
Lostsunrise [7]

Step-by-step explanation:

<em>Hello</em><em>!</em><em>!</em><em>!</em>

<em>Given</em><em>, </em><em> </em><em>VXW</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>Right angled triangle</em><em> </em><em>where</em><em> </em><em>WV</em><em> </em><em>=</em><em>4</em><em> </em><em>and</em><em> </em><em>XV</em><em> </em><em>=</em><em>5</em><em>.</em>

<em>now</em><em>,</em><em> </em><em>b</em><em>y</em><em> </em><em>taking</em><em> </em><em>reference angle</em><em> </em><em>as angle </em><em>W</em><em>,</em><em> </em><em>and</em><em> </em><em>using</em><em> </em><em>tangent</em><em> </em><em>we</em><em> </em><em>get</em><em>;</em>

<em>p</em><em>=</em><em>5</em>

<em>b</em><em>=</em><em>4</em>

<em>again</em><em>, </em>

<em>tan</em><em> </em><em>thita</em><em> </em><em>=</em><em>p</em><em>/</em><em>b</em>

<em>tan</em><em> </em><em>thita</em><em> </em><em>=</em><em> </em><em>5</em><em>/</em><em>4</em>

<em>so</em><em>,</em><em> </em><em>tan</em><em> </em><em>thita</em><em> </em><em>=</em><em>1</em><em>.</em><em>2</em><em>5</em><em>.</em>

<em>now</em><em>,</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>angle</em><em> </em><em>W</em><em>,</em><em> </em><em>we</em><em> </em><em>should</em><em> </em><em>d</em><em>o</em><em> </em><em>tan</em><em> </em><em>thita</em><em> </em><em>inverse</em><em>;</em>

<em>or</em><em>,</em><em> </em><em>(</em><em>tan</em><em> </em><em>thita</em><em>)</em><em>-1</em><em>=</em><em> </em><em>tan</em><em> </em><em>thita</em><em>-1</em><em>(</em><em>1</em><em>.</em><em>2</em><em>5</em><em>)</em>

<em>or</em><em>,</em><em> </em><em>(</em><em>tan</em><em> </em><em>thita</em><em>)</em><em> </em><em>-1</em><em> </em><em>=</em><em>5</em><em>1</em><em>.</em><em>3</em><em>4</em><em>0</em><em>1</em><em>°</em><em>.</em>

<em>Now</em><em>,</em><em> </em><em>by</em><em> </em><em>rounding</em><em> </em><em>off</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em>tan</em><em> </em><em>thita</em><em> </em><em>(</em><em>angle</em><em> </em><em>W</em><em> </em><em>)</em><em>=</em><em> </em><em>5</em><em>1</em><em>°</em><em>.</em>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

8 0
3 years ago
#20, what is this answer ?
Charra [1.4K]

Answer:

b = 2A/h

b = 6 inches

Step-by-step explanation:

A = \frac{1}{2} bh \\  \\ 2A =bh \\  \\  \purple{b =  \frac{2A}{h}}  \\  \\ plug \: A = 12 \: and \: h = 4 \\  \\ b =  \frac{2 \times \cancel{12}}{ \cancel4}  \\  \\ b = 2 \times 3 \\  \\ b \:  = 6  \: in

8 0
3 years ago
The surface areas of two similar figures are 25 in2 and 36 in2. If the volume of the smaller figure is 250 in3, what is the volu
Slav-nsk [51]
Since the figures are similar, we can establish a rule of three as follows.
We know that the area of the smaller figure is 25in^{2}, and its volume is 250in^{3}. We also know that the area of the larger figure is 36in^{2}; since we don't now its volume, lets represent it with X:
\frac{25in^{2}----\ \textgreater \ 250in^{3}}{36in^{2}----\ \textgreater \ Xin^{3}} 
\frac{25}{36} = \frac{250}{X}
X= \frac{(250)(36)}{25}
X=360

We can conclude that the volume of the larger figure is 360in^{3}; therefore, the correct answer is a.
6 0
3 years ago
Read 2 more answers
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