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lisov135 [29]
1 year ago
13

How would you know the answer (important)

Mathematics
1 answer:
SSSSS [86.1K]1 year ago
7 0

Answer:

okay so I can't see the last option on ur sheet but when u graph this equation the point that lies on the curve is (2,-3) so that is the vertex but if I move up this curved line it passes through the Y axis at (0,-1), the Last answer that I can't see it wouldn't happen to be (-1,6) would it

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TRYNNA FINISH THIS .. ILL MARK THE BRAINLIEST
Ann [662]

Answer:

A

Step-by-step explanation:

1 pound = 16 ounces

so pounds are multiplied by 16 to convert to ounces

3 0
3 years ago
Read 2 more answers
How to solve the second equation
ivann1987 [24]
\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{lccclll}
y = &{{ -0.02}}x^2&{{ +1}}x&{{ +6}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left( -\cfrac{1^2}{2(-0.02)}~~,~~6-\cfrac{1^2}{4(-0.02)} \right)
\\\\\\
(\stackrel{\textit{how far ahead it went}}{25}~,~\stackrel{\textit{how high it went}}{18\frac{1}{2}})

\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{lccclll}
y = &{{ -0.01}}x^2&{{ +0.7}}x&{{ +6}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left( -\cfrac{0.7^2}{2(-0.01)}~~,~~6-\cfrac{0.7^2}{4(-0.01)} \right)
\\\\\\
(\stackrel{\textit{how far ahead it went}}{24\frac{1}{2}}~,~\stackrel{\textit{how high it went}}{18\frac{1}{2}})
4 0
3 years ago
Find the missing lengths. leave your answers as radicals in simplest form
LiRa [457]

Check the picture below.

5 0
2 years ago
On a test of 76 ​items, Pedro got 93​% correct.​ (There was partial credit on some​ items.) How many items did he get​ correct?
Firlakuza [10]
You would use the “is/of” method.

93 / 100 = x / 76

Cross multiply and divide:

7068 / 100 = 70.68

This means Pedro got around 70 to 71 questions correct and 5 or 6 questions incorrect.
6 0
3 years ago
PLEASE HELP IM ON A TIME LIMIT :(
Mice21 [21]

Answer:

hey hope this helps

<h3 /><h3>Comparing sides AB and DE </h3>

AB =

\sqrt{ {1}^{2} +  {1}^{2}  }

=  \sqrt{2}

DE

= \sqrt{ {(3 - 5)}^{2} +  {(1 + 1}^{2}  }  \\   = \sqrt{ {( - 2)}^{2}  +  {(2)}^{2} }  \\    = \sqrt{4 + 4}  \\  =  \sqrt{8}  \\   = 2 \sqrt{2}

So DE = 2 × AB

and since the new triangle formed is similar to the original one, their side ratio will be same for all sides.

<u>scale factor</u> = AB/DE

= 2

It's been reflected across the Y-axis

<em>moved thru the translation of 3 units towards the right of positive x- axis </em>

for this let's compare the location of points B and D

For both the y coordinate is same while the x coordinate of B is 0 and that of D is 3

so the triangle has been shifted by 3 units across the positive x axis

7 0
2 years ago
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