3 lines are shown. A line with points M, H, K intersects with a line with points J, H, L at point H. Another line extends from p
oint H to point N in between angle K, H, J. Angle M H L is (3 x + 20) degrees, angle K H N is (x + 25) degrees, and angle J H N is (x + 20) degrees.
What is the measure of AngleJHN?
25°
45°
50°
95°
What is the measure of AngleJHN?
25°
45°
50°
95°
1 answer:
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Answer:
Step-by-step explanation:
A line perpendicular to the given line has a slope that is the negative inverse of the reference line.
Rewrite the given equation in the format of y=mx+b, where mi is the slope and b is the y-intercept (the value of y when x = 0.
2x + 3y = 4
3y=-2x+4
y = -(2/3)X + (4/3)
The reference slope is -(2/3). The negative inverse is (3/2), which will be the slope of a perpendicular line. We can write the new line as:
y = (3/2)x + b
Any value of b will still result in a line that is perpendicular. But we want a value of b that will shift the line so that it intersects the point (-3,-5). Simply enter this point in the above equation and solve for b.
y = (3/2)x + b
-5 = (3/2)(-3) + b
-5 = -(9/2) + b
-5 = -4.5 + b
b = - 0.5
The equation of the line that is perpendicular to 2x + 3y = 4 and includes point (-3,-5) is
y = (3/2)x - 0.5
