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Helga [31]
4 years ago
9

Which fraction divided by 3/6 is equal to -9/10

Mathematics
1 answer:
Ganezh [65]4 years ago
3 0

Answer:

<h2>3/6 is the same as 9/18.</h2>

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Line segment TU has endpoints (-7,10) and (-6,-5). What is the length of TU to the NEAREST TENTH?
Sindrei [870]

Answer: 15 units

Step-by-step explanation:

Given

The endpoints of the line segment are (-7,10)\ \text{and}\ (-6,-5)

The length of the line segment is given by the distance formula i.e.  

d=\sqrt{\left( x_2-x_1\right)^2+\left( y_2-y_1\right)^2}

Insert the values,

\Rightarrow d=\sqrt{\left( -6+7\right)^2+\left( -5-10\right)^2}\\\Rightarrow d=\sqrt{1^2+\left( -15\right)^2}\\\Rightarrow d=\sqrt{1+225}\\\Rightarrow d=15.0\ \text{units}

Therefore, the length of line segment TU is 15 units

7 0
3 years ago
A (5,3) and B(3,-2) are two fixed points. Find the equation of the locus of P, so that the
andre [41]

Answer:

37=5x-2y,\,1=5x-2y

Step-by-step explanation:

If (x_1,y_1),\,(x_2,y_2),\,(x_3,y_3) are coordinates of a triangle then area of a triangle is equal to \frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|

Let point P be (x,y)

Put (x_1,y_1)=(5,3),\,(x_2,y_2)=(3,-2),\,(x_3,y_3)=(x,y)

Area of a triangle = \frac{1}{2}|5(-2-y)+3(y-3)+x(3+2)|

=\frac{1}{2}|-10-5y+3y-9+5x|\\\\=\frac{1}{2}|-19+5x-2y|

Also,

Area of a triangle = 9 square units

9=\frac{1}{2}|-19+5x-2y|\\\\18=|-19+5x-2y|

±18 = -19 + 5x - 2y

18=-19+5x-2y,\,-18=-19+5x-2y\\\\37=5x-2y,\,1=5x-2y

3 0
3 years ago
12x - 3x + 4 = 5x - 16<br> Please show me how you got it!
FinnZ [79.3K]

Answer:

x = -5

Step-by-step explanation:

Combine them like terms,then you subtract 4 from both sides,and then Simplify

8 0
3 years ago
Read 2 more answers
what are the solutions of 4x^2-8x+5=0 A. x=2+i/2 or x=2-i/2. B. x=1+i/2 or x=1-i/2 C. x=1+i or x=1-i D. x=2+i or x=2-i
rewona [7]
The correct answer is Option A.
5 0
3 years ago
I need help please! I really do! Thank you.
SCORPION-xisa [38]
\bf \qquad \textit{parabola vertex form}\\\\&#10;&#10;\begin{array}{llll}&#10;{y=(x-{{ h}})^2+{{ k}}}\\\\&#10;\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})

notice your vertex there, 1, -3
h = 1
k = -3
7 0
3 years ago
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