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emmasim [6.3K]
2 years ago
14

Fill in the blank with the least common denominator 5/6 + x = 7/12​

Mathematics
1 answer:
irinina [24]2 years ago
7 0

Answer: The least common denominator is 12

x= -3/12

Simplified:  -1/4

Step-by-step explanation:

Do 7/12 - 5/6

     7/12 - 10/12

    = -3/12

Simplified: -1/4

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Solve for x<br> 5x + 7 = 11<br> Give your answer as a fraction in its simplest form.
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Step-by-step explanation:

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6 0
3 years ago
Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have
boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after  10 days and 20 days, respectively.

We will use half life formula.

A=a\cdot(\frac{1}{2})^{\frac{t}{h}}, where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{1}

A=1\text{ kg}\cdot\frac{1}{2}

A=0.5\text{ kg}

Therefore, amount of the material left after 10 days would be 0.5 kg.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{2}

A=1\text{ kg}\cdot\frac{1^2}{2^2}

A=1\text{ kg}\cdot\frac{1}{4}

A=0.25\text{ kg}

Therefore, amount of the material left after 20 days would be 0.25 kg.

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4 years ago
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Answer:

The answers I have come are as follows.

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