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2 years ago

The first five terms of a quadratic sequence is 1,8,21,40,65 .

Mathematics

2 answers:

Paladinen [302]2 years ago

6 0

Answer: Nth term = 5

Explanation:

An = a + ( n - 1 ) d

a = first term and

d = the difference

An = 1 + ( n - 1 ) 6

= 1n - 1 + 6

CLT

N = -1+6

N = +5 /5

Mark brainliest

maks197457 [2]2 years ago

4 0

Answer:

Formula To Find: $a_{n} = 3n^2 - 2n$

Step-by-step explanation:

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ANSWER:

$\:D.\text{ }f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge-4$

STEP-BY-STEP EXPLANATION:

We have the following equation:

$f(x)=\sqrt{x}-4$

The inverse is the following (we calculate it by replacing f(x) by x and x by f(x)):

$\begin{gathered} x=\sqrt{f^{-1}(x)}-4 \\ \\ \sqrt{f^{-1}(x)}=x+4 \\ \\ f^{-1}(x)=(x+4)^2 \end{gathered}$

The domain would be the range of the original equation, and it would be the range of values that f(x) could take, which was from -4 to positive infinity, that is, f(x) ≥ -4.

Therefore, the domain is x ≥ -4.

So the correct answer is D.

$\:f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge -4$

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