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Helga [31]
3 years ago
11

Jason ran 325 meters father than kim ran kim ran 4.2km how many meters did jason run

Mathematics
2 answers:
kow [346]3 years ago
8 0
The difference between Jasons in Kim’s meters ran are 3875
Iteru [2.4K]3 years ago
4 0
To answer this, we change how far Kim ran from kilometres into metres:

-------------------------------------------------------------------------------------------------------------
There are 1,000 metres in a kilometre. 
So we multiply 4.2km by 1000, to get the distance into metres:

4.2 x 1000 = 4200 meters
-------------------------------------------------------------------------------------------------------------
Since Jason ran 325 metres farther than kim, we add 325 onto 4200:

4200 + 325 = 4535 metres
-------------------------------------------------------------------------------------------------------------
Answer:
 
So Jason ran a 4,535 metres.

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PLZ HELP!
Natasha2012 [34]

Answer:

4 times greater

Step-by-step explanation:

Prism A

SA = 2 (lw+wh+lh)  where l is length w is width and h is height

SA = 2 ( 5*6+ 6*7+ 5*7)

SA = 2(30+42+35)

SA = 2(107)

SA =214

Prism B

SA = 2 (lw+wh+lh)  where l is length w is width and h is height

SA = 2 ( 10*12+ 12*14+ 10*14)

SA = 2(120+168+140)

SA = 2(428)

SA =856

Robert is not correct

856/214 =4

Prism B is 4 times greater

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3 years ago
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34kurt

Answer:

Value of 53 is 53

Step-by-step explanation:

4 0
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Solve the equation ( 1 point) 3/4x=9<br><br> A) X=12<br> B) X=108<br> C) X=72<br> D) X= 4/9
Elena L [17]

Answer:

x = 12

Step-by-step explanation:

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(3 x)/4 = 9

Multiply both sides of (3 x)/4 = 9 by 4/3:

(4×3 x)/(3×4) = 4/3×9

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(4×3 x)/(3×4) = (3×4)/(3×4)×x = x:

x = (4×9)/3

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Answer:  x = 12

3 0
4 years ago
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Otrada [13]

Answer:

B.

Step-by-step explanation:

4*s = 4s

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Use the property of distribution

<em>hope this helps :)</em>

3 0
3 years ago
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matrenka [14]

Answer:

           q\approx-2.12

Explanation:

The exponent of 0.52 is not 9 but q. Thus, you need so solve the equattion to find the value of the exponent, q.

To solve exponential equations with different bases, you must use logarithms, which is the inverse function of exponentiation:

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