Let us say that:
a = ones
b = fives
c = twenties
So that the total money is:
1 * a + 5 * b + 20 * c = 229
=> a + 5b + 20c = 229 -->
eqtn 1
We are also given that:
c = a – 5 -->
eqtn 2
a + b + c = 30 -->
eqtn 3
Rewriting eqtn 3 in terms of b:
b = 30 – a – c
Plugging in eqtn 2 into this:
b = 30 – a – (a – 5)
b = 35 – 2a -->
eqtn 4
Plugging in eqtn 2 and 4 into eqtn 1:
a + 5(35 – 2a) + 20(a – 5) = 229
a + 175 – 10a + 20a – 100 = 229
11a = 154
a = 14
So,
b = 35 – 2a = 7
c = a – 5 = 9
Therefore there are 14 ones, 7 fives, and 9 twenties.
Answer:
try A,C and E because A) has more students than any other ones C) if I goes up in twos and E) same as C
Answer:
A.) Angle R, Angle S, Angle T
Step-by-step explanation:
It's a because it asked in order for an obtuse, an acute, and right. So in order it's R (for obtuse), S (for acute), and T (for right)
Answer:
2√2
Step-by-step explanation:
compare this equation with the standard equation of a circle centered at (h, k) with radius r:
(x - h)^2 + (y - k)^2 = r^2
(x - 5)^2 + (y + 7)^2=8
Clearly, r^2 = (radius)^2 = 8, and so the radius, r, is √8, or 2√2
You divide 91/14 to get w=6.5.
