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masha68 [24]
2 years ago
5

If the function f(x) = x 2 has the domain {0, 1, 4, 9}, what is its range?

Mathematics
1 answer:
Alexandra [31]2 years ago
3 0
It’s just a simple is that 3.5
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Assume, for the sake of this question, that the data were collected through a well-designed, well-implemented random sampling me
amid [387]

Answer:

Since the pvalue of the test is 0.2743 > 0.1, the threshold probably was met.

Step-by-step explanation:

The widget manufacturing company had established a threshold of 60% preferring the proposed new widget to move forward with producing the new widgets.

This means that at the null hypothesis we test if the proportion is at least 60%, that is:

H_{0}: p \geq 0.6

And the alternate hypothesis is:

H_{a}: p < 0.6

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.6 is tested at the null hypothesis:

This means that:

\mu = 0.6

\sigma = \sqrt{0.6*0.4}

Three hundred thirty-eight of 575 respondents reported preferring the proposed new widget.

This means that n = 575, X = \frac{338}{575} = 0.5878

Value of the test-statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.5878 - 0.6}{\frac{\sqrt{0.6*0.4}}{\sqrt{575}}}

z = -0.6

Pvalue of the test and decision:

We want to find the probability of a proportion of 0.5878 or lower, which is the pvalue of z = -0.6.

Looking at the z-table, z = -0.6 has a pvalue of 0.2743.

Since 0.2743 > 0.1, the threshold probably was met.

3 0
3 years ago
How do I solve for the missing length? Please explain!! I’m struggling
REY [17]
Let call it x 
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5 0
3 years ago
In which quadrant or on which axis do each of the points (-2,4) , (3,-1) ,(-1,0), (1,2) and
exis [7]

Answer:

Step-by-step explanation:

cartesian plane :

quadrant 1 : both x and y are positive

quadrant 2 : x is negative, y is positive

quadrant 3 : both x and y are negative

quadrant 4 : x is positive and y is negative

(-2,4)......we have x is negative and y is positive...so we are in quadrant 2

(3,-1)....we have x is positive and y is negative...in quadrant 4

(-1,0) ...if u have a 0 in ur points, they do not lie in any quadrant because they are located on an axis....this is located on axis x

(1,2)....both are positive....located in quadrant 1

(-3,-5)...both are negative.....quadrant 3

5 0
3 years ago
What value of g makes the equation 2g+6-14g=-6(g-5) true?​
Sergeu [11.5K]

Answer:

g=-4

Step-by-step explanation:

2g+6-14g=-6(g-5)

-12g+6=-6g+30

-6g+6=30

-6g=24

g=-4

8 0
3 years ago
Choose the equation below that represents the line passing through the point -3, -1 with a slope of 4
andre [41]

Answer:

Y=4x-5

Step-by-step explanation:

4 0
3 years ago
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