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tatuchka [14]
2 years ago
12

I need to use factorial the! When you use the binomial probability formula and I need to show step-by-step for for a through c

Mathematics
1 answer:
HACTEHA [7]2 years ago
6 0

Using the binomial distribution, it is found that the probabilities are:

  • P(X = 4) = 0.1268.
  • P(X = 2) = 0.2835.
  • P(X \leq 3) = 0.9841

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

Exercise 1:

The parameters are:

n = 15, p = 0.4, x = 4.

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{15,4}.(0.4)^{4}.(0.6)^{11} = 0.1228

Exercise 2:

The parameters are:

n = 12, p = 0.2, x = 2.

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{12,2}.(0.2)^{2}.(0.8)^{10} = 0.2835

Exercise 3:

The parameters are:

n = 20, p = 0.05.

The probability is:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

Using the binomial formula for each value and adding them:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3585 + 0.3774 + 0.1887 + 0.0596 = 0.9841

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

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Which symbol correctly compares the two fractions?
dedylja [7]

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Read 2 more answers
Types of bonds are divided into three categories: good risk, medium risk, and poor risk. Assume that of a total of 11, 332 bonds
Alekssandra [29.7K]

Answer:

Probabilty of not poor= 0.75

Step-by-step explanation:

total of 11332 bonds.

7311 are good risk.

1182 are medium risk.

Poor risk

= total risk-(good risk+ medium risk)

= 11332-(7311+1182)

= 11332-8493

= 2839.

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