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anzhelika [568]
3 years ago
14

Let g be the function given by g(x)=

Mathematics
1 answer:
shepuryov [24]3 years ago
4 0
I think you left out some information. You didn't finish typing the question or a question at all. All you did was type a statement.
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Bart uses 3/12 cup milk to make muffin. Write a fraction that is equivalent to 3/12
vichka [17]
Your fraction that is equal to 3/12 is 1/4
8 0
2 years ago
Please help !!!!!!!!!!!!!​
arlik [135]

Answer:

Step-by-step explanation:

7 0
3 years ago
What is the third quartile of this data set? <br> 20, 21, 24, 25, 28, 29, 35, 37, 42
nata0808 [166]

Answer:

36

Step-by-step explanation:

⇒The question is on third quartile

⇒To find the third quartile we calculate the median of the upper half of the data

Arrange the data in an increasing order

20, 21, 24, 25, 28, 29, 35, 37, 42

Locate the median, the center value

<u>20, 21, 24, 25</u>, 28, <u>29, 35, 37, 42</u>

<u />

The values 20, 21, 24, 25 ------------lower half used in finding first quartile Q1

The value 28 is the median

The vlaues 29, 35, 37, 42...............upper half used in finding 3rd quartile Q3

Finding third quartile Q3= median of the upper half

upper half= 29,35,37,42

median =( 35+37)/2 = 36

6 0
3 years ago
Read the word problem. Hershel buys 5 bags of cookies, 3 bags of granola, and several bags of fruit snacks from a bake sale. In
agasfer [191]

Answer : Hershel buys 2 bags of fruit snacks.

Explanation :

Since we have given that

Number of bags of granola =3

Number of bags of cookies = 5

Total number of bags he buys from the bake sale =10

\text{Remaining bags are of fruit snacks} =10-(5+3)=10-8=2

So, number of bags of fruit snacks = 2

Hence, Hershel buys 2 bags of fruit snacks .

It is a comparison type of word problem.  

As we just compare the items with the total items to get the remaining items.

5 0
2 years ago
The ratio of the circumferences of two circles 2 : 5. Find the ratio of their areas
ratelena [41]
Circumference one = (2R)*pi let that value be 2x
C second = 5x = (2R)*pi * 5 / 2 = (5R)*pi
So Radius one / Radius two = 2 / 5
Area1:Area2=pi(2R)^2:pi(5R)^2=pi(4R^2):pi(25R^2), pi cancel out we get
4R^2:25R^2, now R^2 cancel out and we get ratio of
4:25
5 0
3 years ago
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